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4 years ago

A particular wave can be described as transverse and self-propagating. What type of wave could it be?

2 answers:

6 0

Radio waves are transverse. Self-propagating, I guess means without any specific support, like a string or a body, so radio waves can propagate in vacuum.

So, the last one, radio wave

Ivahew [28]4 years ago

3 0

Answer:

A radio wave

Explanation:

Self propagating waves are those type of waves in which wave will induce the effect of by its own components.

One of the best example for this is Electromagnetic waves.

In electromagnetic waves electric field components and magnetic field components will oscillate perpendicular to each other and they both are perpendicular to the direction of propagation of wave also.

So here the disturbance due to electric field and magnetic field is since perpendicular to wave propagation so it is known as transverse wave.

So here we can say that correct answer must be an electromagnetic type of wave

so it must be

A Radio Wave.

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According to the Academic Honesty Policy, plagiarism is ______.

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UMUC. this is for the blank answer.

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4 years ago

A ball rolls at a speed of 6cm/s how far does the ball roll in 40 seconds ? ____cm

konstantin123 [22]

240 cm you do 6x 40 and should get 240cm

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3 years ago

A student throws a set of keys vertically upward to his fraternity brother, who is in a window 3.60 m above. The brother's outst

Contact [7]

Answer:

$v_{i}=10.10 m/s$

Explanation:

The equation of the position is:

$y=y_{i}+v_{i}t-0.5gt^{2}$

Where:

v(i) is the initial velocity

The initial position y(i) will be zero and the final position y = 3.60 m.

So, we just need to solve this equation for v(i).

$v_{i}=\frac{y+0.5gt^{2}}{t}$

$v_{i}=\frac{3.6+0.5*9.81*1.6^{2}}{1.6}$

$v_{i}=10.10 m/s$

Therefore, the initial velocity is 10.10 m/s upwards.

I hope it helps you!

5 0

3 years ago

A package of mass 5 kg sits on an airless asteroid of mass 7.6 × 1020 kg and radius 8.0 × 105 m. We want to launch the package i

Effectus [21]

Answer:

s = 1.7 m

Explanation:

from the question we are given the following:

Mass of package (m) = 5 kg

mass of the asteriod (M) = 7.6 x 10^{20} kg

radius = 8 x 10^5 m

velocity of package (v) = 170 m/s

spring constant (k) = 2.8 N/m

compression (s) = ?

Assuming that no non conservative force is acting on the system here, the initial and final energies of the system will be the same. Therefore

• Ei = Ef

• Ei = energy in the spring + gravitational potential energy of the system

• Ei = \frac{1}{2}ks^{2} + \frac{GMm}{r}

• Ef = kinetic energy of the object

• Ef = \frac{1}{2}mv^{2}

• \frac{1}{2}ks^{2} + (-\frac{GMm}{r}) = \frac{1}{2}mv^{2}

• s = $\sqrt{\frac{m}[k}(v^{2}+\frac{2GM}{r})}$

s = $\sqrt{\frac{5}[2.8 x 10^5}(170^{2}+\frac{2 x 6.67 x10^{-11} x 7.6 x 10^{20}}{8 x 10^5})}$

s = 1.7 m

7 0

3 years ago

What is the speed of light (in m/s) in air? (Enter your answer to at least four significant figures. Assume the speed of light i

jenyasd209 [6]

Answer:

The speed of light in air is 2.996x10⁸ m/s, and polystyrene is 1.873x10⁸ m/s.

Explanation:

To find the speed of light in air and in polystyrene we need to use the following equation:

$c_{m} = \frac{c}{n}$

Where:

$c_{m}$ : is the speed of light in the medium

n: is the refractive index of the medium

In air:

$c_{a} = \frac{c}{n_{a}} = \frac{2.997 \cdot 10^{8} m/s}{1.0003} = 2.996 \cdot 10^{8} m/s$

In polystyrene:

$c_{p} = \frac{c}{n_{p}} = \frac{2.997 \cdot 10^{8} m/s}{1.6} = 1.873 \cdot 10^{8} m/s$

Therefore, the speed of light in air is 2.996x10⁸ m/s, and polystyrene is 1.873x10⁸ m/s.

I hope it helps you!

8 0

3 years ago