Answer:
the protons will jump to the negatively charged object making it negatively charged
According to the question, the determined melting point of the compound is 112.5-113.0oC. When the solidified compound was retried, the melting point was found to be 133.6-154.5oC. This greater range higher than 112°C is caused by reusing samples leads to errors.
A pure sample is known by its sharp melting point. A pure sample does not melt over a large range. We can see this in the predetermined melting points of the pure sample(112.5-113.0oC).
However, reusing a sample introduces errors because the pure sample may become contaminated leading to a larger and higher range of melting point (133.6-154.5oC) which is far above 112°C.
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There are 1.2 hr would this current have to be applied to plate out 7. 20 g of iron .
Calculation ,
Given ; Current ( I ) = 5. 68 A
In 
, the valancy of Fe is +2 .
2 moles of 
are required for the decomposition of 1 mole of Fe .
7. 20 g of Fe in moles = 7. 20 g /55.845 g/mol =0.12 mole
x moles of are required for the decomposition of 0.128 mole of Fe .
moles of are required = 0.256 moles
Charge on 1 mole of = 96500 C
Charge on 0.256 mole of = 24704 C
Current ( I )= Q/t
t =Q / I = 24704 C/5. 68 A = 4349 sec = 1.2 hr
Therefore , there are 1.2 hr would this current have to be applied to plate out 7. 20 g of iron .
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Pressure is inversely proportional to volume. Therefore, the effect of pressure change is opposite to the effect of volume change. So when more gas is added to the chamber the total pressure of the chamber doesn't increase.
<h3>What are the different relations between pressure and volume?</h3>
- As the volume changes, the concentrations and partial pressures of both reactants and products change.
- As the volume decreases, the reaction shifts to the reaction side with fewer gas particles.
- As the volume increases, the reaction shifts to the side of the reaction containing more gas particles.
- As the pressure increases, the equilibrium shifts towards reactions with fewer moles of gas.
- As the pressure decreases, the equilibrium shifts to the side of the reaction with higher moles of gas.
- Moreover, the pressure change in the system due to the addition of the inert gas is not limited to this.
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