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Zepler [3.9K]
3 years ago
9

What is a product for 4 reaction type?

Chemistry
1 answer:
Crank3 years ago
6 0

Answer:

1= 2H₂ + O₂ → 2H₂O

2=CaCo₃ + heat → CaO +CO₂

3=CH₄ + 2O₂   → CO₂ +2H₂O

4=HCl + NaOH   → NaCl + H₂O

Explanation:

1 = Simple composition

The formation of water molecule is simple composition reaction. In this reaction two hydrogen atoms react with one oxygen atom and form one water molecules.

2H₂ + O₂ → 2H₂O

The amount of energy released is -285.83 KJ/mol. It is exothermic reaction.

2 = Simple decomposition reaction:

The break down of sodium hydrogen carbonate into sodium carbonate, carbondioxide and water is decomposition reaction. The decomposition reactions re mostly endothermic, because compound required energy to break.

2NaHCO₃ + heat → Na₂CO₃ + H₂O + CO₂

It is endothermic reaction.

Another example is:

CaCo₃ + heat → CaO +CO₂

3 = Combustion reaction

Consider the combustion of methane:

CH₄ + 2O₂   → CO₂ +2H₂O

The burning of methane is exothermic. The combustion reactions are exothermic because when fuel are burns they gives energy.

4 = Neutralization reaction

The neutralization reactions are those in which acid and base react to form the salt and the water. Some neutralization reactions are exothermic because they release heat. e.g

Consider the neutralization reaction of HCl and NaOH.

HCl + NaOH   → NaCl + H₂O

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A volume of 30.0 mL of a 0.140 M HNO3 solution is titrated with 0.570 M KOH. Calculate the volume of KOH required to reach the e
igomit [66]

Answer:

7.37 mL of KOH

Explanation:

So here we have the following chemical formula ( already balanced ), as HNO3 reacts with KOH to form the products KNO3 and H2O. As you can tell, this is a double replacement reaction,

HNO3 + KOH → KNO3 + H2O

Step 1 : The moles of HNO3 here can be calculated through the given molar mass (  0.140 M HNO3 ) and the mL of this nitric acid. Of course the molar mass is given by mol / L, so we would have to convert mL to L.

Mol of NHO3 = 0.140 M * 30 / 1000 L = 0.140 M * 0.03 L = .0042 mol

Step 2 : We can now convert the moles of HNO3 to moles of KOH through dimensional analysis,

0.0042 mol HNO2 * ( 1 mol KOH / 1 mol HNO2 ) = 0.0042 mol KOH

From the formula we can see that there is 1 mole of KOH present per 1 moles of HNO2, in a 1 : 1 ratio. As expected the number of moles of each should be the same,

Step 3 : Now we can calculate the volume of KOH knowing it's moles, and molar mass ( 0.570 M ).

Volume of KOH = 0.0042 mol * ( 1 L / 0.570 mol ) * ( 1000 mL / 1 L ) = 7.37 mL of KOH

5 0
4 years ago
How many fluorine atoms bond with calcium to form calcium fluoride?
allsm [11]
2 atoms will bond with calcium to form Calcium Fluoride 
3 0
3 years ago
Which one of the following complexes can exhibit geometrical isomerism? Which one of the following complexes can exhibit geometr
just olya [345]

Answer:

[Pt(NH_{3}_{2})Cl_{2}] shows geometrical isomerism.

Explanation:

<u>Geometrical isomerism:</u>

<em>"Molecules having same molecular formula but the but difference in the arrangement of atoms."</em>

Cis and trans isomers are called geometrical isomers.

Among the given , [Pt(NH_{3}_{2})Cl_{2}] shows geometrical isomerism.

The <em>cis </em>and <em>trans</em> forms of the [Pt(NH_{3}_{2})Cl_{2}] are as follows.

5 0
3 years ago
What kind of nuclear reaction is seen in 146/62 Sm -&gt; 142/60 Nd + 4/2 He?
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<span>Answer is an </span>alpha emission<span>

Alpha decay is an emission of </span>₂⁴He <span>nucleus. If an element undergoes an alpha decay, the mass of the daughter nucleus formed is reduced by 4 compared to mass of parent atom and atomic number is reduced by 2 compared to atomic number of parent atom.

</span><span>Here parent atom is </span>Sm<span> which has atomic number as 62 and mass number as 146. Since the emitted particle is a </span>₂⁴He<span> nucleus this is an alpha decay. Daughter atom will have </span>146 - 4 = 142<span> <span>as mass number and </span></span>62 - 2 = 60<span> <span>as atomic number. Hence, daughter atom should be </span></span>Nd<span> which has atomic number as 60.</span><span>

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4 0
3 years ago
Read 2 more answers
Explain the steps you would follow to make 500 mL of a 0.3 M solution of sucrose
RSB [31]

Answer:

see explanation

Explanation:

Solutions are prepared from one of three solute sources ...

- solid solute from manufacturer,

-liquid solute from manufacturer,

-stock concentrate of solute for dilution to lower concentrations.

In this problem, sucrose is a stock solid with a formula mass of 342.3 grams/mol. The amount of solid needed can be determined using the formula:

mass of solute needed (grams) = (Molarity needed x Volume needed in Liters x formula weight) / (decimal fraction purity of stock solid)

Molarity needed = 0.3M

Volume needed = 500 ml = 0.500 liters

Formula weight = 342.3 grams/mole

Purity factor (assumed) = 100% = 1.00 (should be posted on stock bottle label) For example, a 95% pure stock solid => purity factor of 0.95.

∴ grams of sucrose needed = (0.3M*)(0.500L)(342.3g/mole)/(1.00) =51.345 grams sucrose.

Measure 51.345 grams of sucrose into mixing vessel and add solvent water up to, but not to exceed 500 ml total volume. Mix until homogeneous.

4 0
3 years ago
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