Answer:
²³⁸₉₂U → ²³⁴₉₀Th + ⁴₂He
Explanation:
Nuclei higher than Bi - 92 naturally are radioactive.
In a transmutation reaction, a new element is produced from an existing one due to radioactivity.
Nuclear fission is the radioactive process by which a heavy nucleus spontaneously decays into lighter ones with the release of a large amount of energy.
One example is the transmutation of uranium into thorium;
²³⁸₉₂U → ²³⁴₉₀Th + ⁴₂He
<span>2<span>C6</span><span>H6</span>O(l)+17<span>O2</span>−−>12C<span>O2</span>(g)+12<span>H2</span>O(l)</span>
<span>2S<span>O2</span>(g)+<span>O2</span>(g)−−>2S<span>O3</span>(g)</span>
<span><span>N2</span>(g)+<span>O2</span>(g)−−>2NO(g)</span>
<span>2Na(s)+B<span>r2</span>(l)−−>2NaBr(s)</span><span>
On the 1st 3 I have
12 -17 = -5
2 - 3 = -1
2 - 2 = 0
For the last one:
</span><span>Delta n=0</span><span>
</span>
Answer:
Cellular respiration occurs in both , with most reactions taking place in the cytoplasm of prokaryotes and in the mitochondria of eukaryotes. There are three main stages of cellular respiration: glycolysis, the citric acid cycle, and electron transport/oxidative phosphorylation.
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Answer:</h2>
<h3>What I think is : The protons are present at the centre of the atom with rotating electrons around it so when it is rubbed by fur the electrons get passed from the ebonite rod to the fur leaving the rod negatively charged</h3>
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<em><u>Hope</u></em><em><u> this</u></em><em><u> helps</u></em><em><u> you</u></em><em><u> </u></em><em><u>❤️</u></em></h2>
<h2>
<em><u>Mark</u></em><em><u> me</u></em><em><u> as</u></em><em><u> brainliest</u></em><em><u> ❤️</u></em></h2>
<u>Answer:</u> The value of 
for the chemical equation is 
<u>Explanation:</u>
For the given chemical equation:
To calculate the for given value of Gibbs free energy, we use the relation:
where,
= Gibbs free energy = 78 kJ/mol = 78000 J/mol (Conversion factor: 1kJ = 1000J)
R = Gas constant = 
T = temperature = 1000 K
= equilibrium constant in terms of partial pressure = ?
Putting values in above equation, we get:
Hence, the value of for the chemical equation is
