This means that two objects will reach the ground at the same time if they are dropped simultaneously from the same height. ... When air resistance plays a role, the shape of the object becomes important. In air, a feather and a ball do not fall at the same rate.
Answer:
14.2 m
Explanation:
Using conservation of energy:
PE at top = KE at bottom
mgh = ½ mv²
h = v² / (2g)
h = (16.7 m/s)² / (2 × 9.8 m/s²)
h = 14.2 m
Using kinematics:
Given:
v₀ = 16.7 m/s
v = 0 m/s
a = -9.8 m/s²
Find: Δy
v² = v₀² + 2aΔy
(0 m/s)² = (16.7 m/s)² + 2 (-9.8 m/s²) Δy
Δy = 14.2 m
The tension in each of the ropes is 625 N.
Draw a free body diagram for the bag of food as shown in the attached diagram. Since the bag hangs from the midpoint of the rope, the rope makes equal angles θ with the horizontal. The tensions <em>T</em> in both the ropes are also equal.
Resolve the tension T in the ropes into horizontal and vertical components T cosθ and T sinθ respectively, as shown in the figure. At equilibrium,
......(1)
Calculate the value of sinθ using the right angled triangles from the diagram.

Substitute the value of sinθ in equation (1) and simplify to obtain T.

Thus the tension in the rope is 625 N.
Solution :
Part A .
Given : The
and
components of the vector, d =
degree left of
-axis.
So the
component is = -4 x sin (29°) = -1.939 km
component is = 4 x cos (29°) = 3.498 km
Part B
Given : The
and
components of the vector,
, 
So the
component is = -2 cm/s
component is = 0
Part C
Given : The
and
components of the vector,
left of
-axis.
So the
component is = -13 x sin (36°) = -7.6412 
component is = -13 x cos (36°) = -10.517 