Answer:
67.5feet
Step-by-step explanation:
Given parameters:
Model distance between building and gymnasium = 22.5 inches
Scale of model : 1 inch = 3 feet
Unknown:
Actual ground distance = ?
To solve this problem, we first must understand the concept of scale. A scale is a relationship that represents a dimension on a map/model compared to the true ground expression. In order to visualize or represent some real life objects on paper or in a computer, we use models. These models are an abstraction of the real world based on scales. There are different ways of representing a scale.
In this problem;
the scale is given as;
1 inch on model represents 3 feet on ground
Now, to find 22.5 inches, simply cross multiply and solve;
If 1 inch on model represents 3 feet on ground
22.5 inches on a model will be = 
= 67.5feet
Therefore, the actual distance is 67.5feet
Answer:
option (a) It will be closer to 30 than to 20
Step-by-step explanation:
Data provided in the question:
For sample 1:
n₁ = 10
variance, s₁² = 20
For sample 2:
n₂ = 15
variance, s₂² = 30
Now,
The pooled variance is calculated using the formula,
on substituting the given respective values, we get
or
= 26.0869
Hence,
the pooled variance will be closer to 30 than to 20
Therefore,
The correct answer is option (a) It will be closer to 30 than to 20
Answer:
The measure of the angles are 40 degrees and 50 degrees
Step-by-step explanation:
Let
x ----> the measure of one angle in degrees
y ----> the measure of the complementary angle in degrees
we know that
If two angles are complementary, then their sum is equal to 90 degrees
so
----> equation A
we have that
----> equation B
Substitute equation B in equation A and solve for y
Find the value of x
therefore
The measure of the angles are 40 degrees and 50 degrees
Answer:
y=-3x+4
Step-by-step explanation:
Using the formula y=mx+b
mx= slope b= y-intercept
hence,
y=-3x+4 has a y-intercept of (0,4)
Answer:
The slope of the line is -5
