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3 years ago

You are writing a science report and want to find accurate trustworthy information. Which would be the best resource?

Physics

2 answers:

fgiga [73]3 years ago

8 0

<span>an encyclopedia

Happy studying!</span>

stiv31 [10]3 years ago

3 0

Encyclopedia. Its a book giving information on many subjects including science.
hope this helps you out :)

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What minimum speed must the rocket have just before impact in order to save the explorer's life?

34kurt

<span>Answer: Assuming that I understand the geometry correctly, the combine package-rocket will move off the cliff with only a horizontal velocity component. The package will then fall under gravity traversing the height of the cliff (h) in a time T given by h = 0.5*g*T^2 However, the speed of the package-rocket system must be sufficient to cross the river in that time v2 = L/T Conservation of momentum says that m1*v1 = (m1 + m2)*v2 where m1 is the mass of the rocket, v1 is the speed of the rocket, m2 is the mass of the package, and v2 is the speed of the package-rocket system. Expressing v2 in terms of v1 v2 = m1*v1/(m1 + m2) and then expressing the time in terms of v1 T = (m1 + m2)*L/(m1*v1) substituting T in the first expression h = 0.5*g*(m1 + m2)^2*L^2/(m1*v1)^2 solving for v1, the speed before impact is given by v1 = sqrt(0.5*g/h)*(m1 + m2)*L/m1</span>

8 0

3 years ago

What are the differently types of motion in a bicycle?

Ksivusya [100]

The two types of motion exerted in bicycle are:
1. rotary motion
2. linear motion

7 0

3 years ago

The pressure drop needed to force water through a horizontal 1-in diameter pipe if 0.60 psi for every 12-ft length of pipe. Dete

oksian1 [2.3K]

Answer:

The shear stress at a distance 0.3-in away from the pipe wall is 0.06012lb/ft²

The shear stress at a distance 0.5-in away from the pipe wall is 0

Explanation:

Given;

pressure drop per unit length of pipe = 0.6 psi/ft

length of the pipe = 12 feet

diameter of the pipe = 1 -in

Pressure drop per unit length in a circular pipe is given as;

$\frac{\delta P}{L} = \frac{2 \tau}{r} \\\\$

make shear stress (τ) the subject of the formula

$\frac{\delta P}{L} = \frac{2 \tau}{r} \\\\\tau = \frac{\delta P *r}{2L}$

Where;

τ is the shear stress on the pipe wall.

ΔP is the pressure drop

L is the length of the pipe

r is the distance from the pipe wall

Part (a) shear stress at a distance of 0.3-in away from the pipe wall

Radius of the pipe = 0.5 -in

r = 0.5 - 0.3 = 0.2-in = 0.0167 ft

ΔP = 0.6 psi/ft

ΔP, in lb/ft² = 0.6 x 144 = 86.4 lb/ft²

$\tau = \frac{\delta P *r}{2L} = \frac{86.4 *0.0167}{2*12} =0.06012 \ lb/ft^2$

Part (b) shear stress at a distance of 0.5-in away from the pipe wall

r = 0.5 - 0.5 = 0

$\tau = \frac{\delta P *r}{2L} = \frac{86.4 *0}{2*12} =0$

3 0

3 years ago

Help ;-;

nasty-shy [4]

Answer:

all qn 1,2,3 have same answer ,. Yes,. hope it helps

3 0

3 years ago

Two electric motors drive two elevators of equal mass in a three-story building 10 meters tall. Each elevator has a mass of 1,00

algol [13]

Answer:

The power output of the first motor is, P = 2.0 x 10⁴ watts

Explanation:

Given data,

The height of the building, h = 10 m

The mass of the elevator, m = 1000 kg

The time duration of the motor to do this work, t = 5.0 s

The force acting on the elevator,

F = m x g

= 1000 x 9.8

= 9800 N

The work done by the elevator,

W = F x h

= 9800 x 10

= 98000 J

The power output of the first motor,

P = W / t

= 98000 / 5

= 19600 watts

= 1.96 x 10⁴ watts

Hence, the power output of the first motor is, P = 2.0 x 10⁴ watts

3 0

3 years ago