A tennis player swings and hits the ball away. How does the force of the tennis racket affect the motion of the ball

Physics

1 answer:

defon2 years ago

4 0

The force of the racket affects the ball's motion because it changes the momentum of the ball.

<h3>Impulse received by the ball</h3>

The impulse received by the ball through the racket affects the motion because it changes the momentum of the ball.

The ball which is initially at rest, will gain momentum after been hit with the racket.

J = ΔP = Ft

where;

J is the impulse received by the ball
ΔP is change in momentum of the ball
F is the applied force
t is the time of action

Thus, the force of the racket affects the ball's motion because it changes the momentum of the ball.

Learn more about impulse here: brainly.com/question/25700778

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An object is moving in a straight line with a constant acceleration. Its position is measured at three different times, as shown

stiv31 [10]

The constant acceleration of the object is $0.414\ m/s^2$ .

<h3>Acceleration of the object</h3>

The acceleration of the object is constant, and the values at the three different positions is the same.

<h3> For the first position and time</h3>

$s = v_0 t + \frac{1}{2} at^2\\\\37.7 = v_o(9.6) +\frac{1}{2} a(9.6)^2\\\\ 37.7 = 9.6v_0 + 46.08a$

<h3>For the second position and time</h3>

$39.3 = v_o(18.048) +\frac{1}{2} a(18.048)^2\\\\ 39.3 = 18.048v_0 + 162.87a$

<h3>Solve the first and second equation together</h3>

$37.7 = 9.6v_0 + 46.08a\\\\39.3 = 18.048v_0 + 162.87a\\\\18.048: \ \ 680.41 = 173.261v_0 + 831.651a\\\\9.6: \ \ \ \ -(377.28 = 173.261 v_0+ 1563.552a)\\------------------\\303.13 = -731.901a\\\\-a = \frac{303.13}{731.901} \\\\-a = 0.414 \ m/s^2\\\\|a| = 0.414 \ m/s^2$