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Alchen [17]
2 years ago
12

What is the medium the energy in the slinky wave travels through?

Physics
2 answers:
vlabodo [156]2 years ago
6 0

Answer:

The metal coil of the slinky

Explanation:

The wave travels on the actual slinky which we see deforming as the wave goes through.

Sergio [31]2 years ago
4 0

Answer:

A.) The metal coil of the slinky

Explanation:

Hello! This is the correct answer! Have a blessed day! :)

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A box slides downwards at a constant velocity on an inclined surface that has a coefficient of friction uK = .58 The angle of th
mojhsa [17]

Answer: The angle of inclination is nearly 30°

Explanation:

For a body on an inclined plane, the coefficient of friction between the body and the plane is equal to the ratio of the moving force applied to the body to the frictional force acting on the body.

If uK coefficient of friction;

Fm is the moving force

R is the normal reaction on the body

Mathematically uK = Fm/R

Fm = WSin(theta)

R = Wcos(theta)

uK = Wsin(theta)/Wcos(theta)

uK = tan(theta)

theta = arctan(uK)

If uK is 0.58

theta = arctan0.58

theta = 30°

The angle of the inclined will be 30°

7 0
3 years ago
Timed plz hurry
puteri [66]

Answer:

b

Explanation:

emphasizes self-importance

4 0
3 years ago
Read 2 more answers
A 5kg mass is pushed with a force of 10N for a distance of 2.5 meters. The work done is​
Aliun [14]

W = 25 J

Explanation:

Work done on an object is defined as

W = Fd = (10\:\text{N})(2.5\:\text{m}) = 25\:\text{J}

7 0
2 years ago
What is the arrow pointing to?
e-lub [12.9K]

Answer: A. Spine

Hope this helps.

7 0
3 years ago
The orbital period of a satellite is 2 × 106 s and its total radius is 2.5 × 1012 m. The tangential speed of the satellite, writ
LenaWriter [7]

The orbital period of the satellite[T] is given as 2*10^{6} S.

The radius of the satellite is given [R] 2.5*10^{12} m.

we are asked here to calculate the tangential speed of the satellite.

Before going to get the solution first we have understand the tangential speed.

The tangential speed of a satellite is given as the speed required to keep the satellite along the orbit. If satellite speed is less than tangential speed,there is the chance of it falling down towards earth. If it is more,then it will deviate from it orbit and can't stick to the orbit further.In a simple way  the tangential speed is the linear speed of an object in a circular path.

Now we have to calculate the tangential speed [V].

Mathematically the tangential speed [V]   written as -

                                V=\frac{2\pi R}{T}

where T is the time period of the satellite and R is the radius of the satellite.

                        V=\frac{2*3.14*10^{12} }{2*10^{6} }

                               = 7.85*10^{6} m/s

There is also another way through which we can get  the solution as explained below-

We know that the tangential speed of a satellite V=\sqrt{\frac{GM}{R^{2} } }

where G is the gravitational constant and M is the mas of central object.

But we know that g=\frac{GM}{R^{2} }

                               ⇒GM=gR^{2}  where g is the acceleration due to gravity of that central object.


Hence    V=\sqrt{\frac{gR^{2} }{R} }

               ⇒   V=\sqrt{gR}

By knowing the value of g due to that central object we can also calculate its tangential speed.

                           

 




7 0
3 years ago
Read 2 more answers
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