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Ne4ueva [31]
3 years ago
10

Why would the time of flight depend on the angle of the launch

Physics
1 answer:
DIA [1.3K]3 years ago
3 0
The time of flight depends on the vertical speed. The angle of the launch determines how much of the total launch velocity is horizontal speed and how much of it is vertical speed.
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1 point
Yuliya22 [10]
PE= 3kg x 10N/kg x 10m
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8 0
3 years ago
PLEASE HELP The graph shows the amplitude of a passing wave over time in seconds (s). What is the approximate frequency of the w
d1i1m1o1n [39]

Answer:

F = 0.3\ Hz

Explanation:

Given

See attachment for the graph

Required

Determine the frequency

Frequency (F) is calculated as:

F = \frac{1}{T}

Where

T = Time to complete a period

From the attachment, the wave complete a cycle or period in 3 seconds..

So:

F = \frac{1}{3s}

F = 0.333\ Hz

F = 0.3\ Hz --- Approximated

7 0
2 years ago
Read 2 more answers
Given:A=6x-2y B:-4x-8y C:-3x+9y. Commute A+B-C
DedPeter [7]
<span>A+B-C
</span><span>A = 6x - 2y
B = -4x - 8y
C = -3x + 9y

(</span>6x - 2y) + (-4x - 8y) - (-3x + 9y)
(6x - 2y) + (-4x - 8y) + (3x - 9y)
2x -10y + (3x - 9y)

5x - 19y
8 0
3 years ago
A skateboarder is moving 5.25 m/s when he starts to roll up a frictionless hill. How much higher is he when his velocity has red
Taya2010 [7]
Mechanical energy E = mgh + 1/2mv²

When he starts, let h = 0 ⇒ E₁ = 1/2mv₁²
When he reaches height h ⇒ E₂ = mgh + 1/2mv₂²

Without friction, energy is conserved at all times.

E₁ = E₂
     ↓
1/2mv₁² = mgh + 1/2mv₂²
     ↓
1/2v₁² = gh + 1/2v₂²
     ↓
gh = 1/2(v₁² - v₂²)
    ↓
h = (v₁² - v₂²) / (2g)


5 0
3 years ago
Read 2 more answers
Which statement is supported by the information in the diagram and table below?
Natasha_Volkova [10]

Answer:

a

Explanation:

a

5 0
2 years ago
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