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valkas [14]
2 years ago
9

A cable with 19.0 N of tension pulls straight up on a 1.50 kg block that is initially at rest. What is the block's speed after b

eing lifted 2.00 m ? Solve this problem using work and energy
Physics
1 answer:
frez [133]2 years ago
7 0

The final speed of the block, after being lifted 2.00 m is 3.39 m/s

<h3>What is speed?</h3>

Speed can be defined as the rate of change in the distance of a body.

To calculate the speed of the block after being lifted 2.00 m,  first, we need to calculate the acceleration of the block using the formula below

Formula:

  • T-mg = ma......... Equation 1

Where:

  • T = Tension in the cable
  • m = mass of the cable
  • a = acceleration
  • g = acceleration due to gravity

Restructuring the formula above,

  • a = (T-mg)/m............... Equation 2

From the question,

Given:

  • T = 19 N
  • m = 1.5 kg
  • g = 9.8 m/s²

Substitute these values into equation 2

  • a = [(19)-(1.5×9.8)]/1.5
  • a = 4.3/1.5
  • a = 2.87 m/s²

Finally, to calculate the speed of the block, we use the formula below.

  • v² = u²+2as.......... Equation 3

Where:

  • v = Final speed
  • u = initial speed
  • a = acceleration
  • s = distance

From the question,

Given:

  • u = 0 m/s
  • a = 2.87 m/s²
  • s = 2.00 m

Substitute these values into equation 3

  • v² = 0²+(2×2×2.87)
  • v² = 11.48
  • v = √11.48
  • v = 3.39 m/s

Hence, The final speed of the block, after being lifted 2.00 m is 3.39 m/s.

Learn more about speed here: brainly.com/question/6504879

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If he were able to maintain this constant rate of acceleration, what would have been his speed as he finished the race?
Law Incorporation [45]

a) 4.8 m/s² his average acceleration during the first 2.5 s

b) 15 m distance he cover during the first 2.5 seconds.

c) 31 m/s his speed as he finished the race.

<h3>(a) How to calculate the Average Acceleration ?</h3>

Average acceleration is calculated by using Newtons first law of motion

v = u + at

where

u is initial velocity

v is final velocity

a is constant acceleration

t is time

Given u = 0m/s , v = 12 m/s and t = 2.5 sec

Therefore average acceleration is given by

a=\frac{v}{t}

a=\frac{12}{2.5}

a = 4.8 m/sec²

b) Here we will use newtons second law of motion

s=ut+\frac{1}{2}at^{2}

On substituting value we get

s = 15m

c) Here we will use newtons third law of motion

v² = u² + 2as

Here u = 0 , a = 4.8 m/s² and s = 100 m

Therefore

v² = 960

v = 31 m/s

Disclaimer: the question was given incomplete in the portal. Here is the complete question.

Question: Usain Bolt's 100m sprint Runner set the world record for the100 meter sprint during the 2009World Championships in Berlin with a time of 9.58 s, reaching a top speed of 12 m/s in about 2.5 s.

a. What was his average acceleration during the first 2.5 s?

b. What distance did he cover during the first 2.5 seconds, assuming his acceleration was constant?

c. If he were able to maintain this constant rate of acceleration, what would have been his speed as he finished the race?

Learn more about Newtons law of motion here:

brainly.com/question/12525794

#SPJ4

5 0
2 years ago
Suppose a light ray is changing direction when it changes from one transparent medium to another. Which of the following changes
MA_775_DIABLO [31]
The correct option is C i..e.
change the second medium to get a greater difference than before in the speed of light in the two mediums


Explanation: whenever light goes from one medium to another, kts frequency remains unchanged. It totally depends on tbe refractive index of the medium, which can change the speed of light.
If the refractive index of the entering medium is less than that of the medium from which light came,then the angle will be wider.
7 0
3 years ago
A ladder placed up against a wall is sliding down. The distance between the top of the ladder and the foot of the wall is decrea
Kitty [74]

Answer:

distance changing at rate of 3.94 inches/sec

Explanation:

Given data

wall decreasing at a rate = 9 inches per second

ladder L = 152 inches

distance  h = 61 inches

to find out

how fast is the distance changing

solution

we know that

h² + b² = L²   ..................1

h² + b² = 152²

Apply here derivative w.r.t. time

2h dh/dt + 2b db/dt = 0

h dh/dt + b db/dt = 0

db/dt = - h/b × dh/dt     .............2

and

we know

h = 61

so h² + b² = L²

61² + b² = 152²

b² = 19383

so b = 139.223

and we know dh/dt = -9 inch/sec

so from equation 2

db/dt = -61/139.223  (-9)

so

db/dt = 3.94 inches/sec

distance changing at rate of 3.94 inches/sec

3 0
3 years ago
Horizontal rows are called ( )<br> and represent ( ) levels. <br> () are why I need answers plz
Rudiy27

Answer:

1. Periods; that are what horizontal rows on a periodic table are called.

2. Each period represents the number of levels

Explanation:

3 0
3 years ago
Which command is capable of creating connecting lines that have a rounded or sharp edge?
natima [27]

Answer:

it is dddd

Explanation:

6 0
2 years ago
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