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3 years ago

What is the molarity of a 250.0 milliliter aqueous solution of sodium hydroxide that contains 15.5 grams of solute? 6.2 M

Chemistry

2 answers:

Alchen [17]3 years ago

8 0

Moles = 15.5 g / 40 g/mol = 0.3875 mol

M = 0.3875 mol / 0.250 L = 1.55M

Digiron [165]3 years ago

6 0

Answer : The molarity is 1.55 M

Explanation :

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

or,

$\text{Molarity}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

In this question the solute is, sodium hydroxide.

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{15.5g\times 1000}{40g/mole\times 250.0L}$

$\text{Molarity}=1.55mole/L=1.55M$

Therefore, the molarity is 1.55 M

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B. Precipitates are formed when two solutions combine to form another solution and a solid.

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Complete combustion of 3.20g of a hydrocarbon produced 9.69g of CO2 and 4.96g of H2O. What is the empirical formula for the hydr

vlabodo [156]

Let empirical formula for hydrocarbon is CxHy

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So moles of carbon present = 0.22 moles

mass of H2O produced = 4.96 g

Moles of H2O produced = mass / molar mass = 4.96 / 18 = 0.28 moles

So moles of H present = 2 X 0.28 = 0.56 moles

Let us divided the moles of each with lowest value of moles

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3 years ago

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3 years ago

How many grams of NO can be produced if 204 g of NO2 is mixed with 58.1 g of H2O?

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Answer:

44.4 grams of NO can be produced

Explanation:

Step 1: Data given

Mass of NO2 = 204 grams

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Mass of H2O = 58.1 grams

Molar mass H2O = 18.02 g/mol

Step 2: The balanced equation

3NO2 + H2O→ 2HNO3 + NO

Step 3: Calculate moles NO2

Moles NO2 = 204 grams / 46.0 g/mol

Moles NO2 = 4.43 moles

Step 4: Calculate moles H2O

Moles H2O = 58.1 grams / 18.02 g/mol

Moles H2O = 3.22 moles

Step 5: Calculate limiting reactant

For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO

NO2 is the limiting reactant. It will completely be consumed (4.43 moles). H2O is in excess. there will react 4.43 /3 = 1.48 moles. There will remain 3.22 - 1.48 = 1.74 moles

Step 6: Calculate moles NO

For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO

For 4.43 moles NO2 we'll have 4.43/3 = 1.48 moles NO

Step 7: Calculate mass NO

Mass NO = 1.48 moles * 30.01 g/mol

Mass NO = 44.4 grams

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The velocity is basically the speed + the direction of an object put into one quantity, velocity.

hope this helps, if not see me in the comments...

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