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2 years ago

HELP ME PLEASE. no links.

Chemistry

1 answer:

tatiyna2 years ago

4 0

Answer:

Experimental group

Explanation:

i hopes this helps let me know if im wrong:)

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What changes in trade did Europeans hope to bring about by finding sea routes to Asian markets?

Dovator [93]

Answer:

controlled by the Arabs, who brought frankincense and myrrh by camel caravan from South Arabia.

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3 years ago

The molar mass of barium nitrate (ba(no3)2) is 261.35 g/mol. what is the mass of 5.30 × 1022 formula units of ba(no3)2? 0.0900 g

liberstina [14]

Molar mass is the ratio of the mass to that amount of the substance. The mass of the barium nitrate in the formula unit is 23.0 grams.

The mass of a substance is the product of the molar mass of the compound and the number of moles of the compound.

Given,

Molar mass of barium nitrate = 261.35 g/mol

If, $6.022 \times 10^{23}$ have a mass of 261.35 g/mol then, $5.30 \times 10^{22}$ formula units will have a mass of,

$\begin{aligned}& = \dfrac{261.35 \times 5.30 \times 10^{22}}{6.022\times 10^{23}}\\\\&= 23.0\;\rm gm\end{aligned}$

Therefore, option C. 23.0 gm is the mass of barium nitrate.

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brainly.com/question/24958554

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1 year ago

How many carbon atoms are in 7.05 moles of pyridine

NemiM [27]

First, it is best to know the chemical formula of pyridine which is C5H5N. To determine the number of carbon atoms present in pyridine, multiply 7.05 mol C5H5N with 5 mol C/ 1 mol C5H5N which then results to 35.35 mol of carbon. Then, multiply the answer to Avogadro's number which is 6.022x10^23 atoms. It is then calculated that the number of carbon atoms in 7.05 moles of pyridine is 2.12x10^25 atoms.

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3 years ago

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Is blood a solution ?

qaws [65]

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3 years ago

Consider the decomposition of a metal oxide to its elements, where M represents a generic metal. M 3 O 4 ( s ) − ⇀ ↽ − 3 M ( s )

Citrus2011 [14]

Answer:

a) ΔGrxn = 6.7 kJ/mol

b) K = 0.066

c) PO2 = 0.16 atm

Explanation:

a) The reaction is:

M₂O₃ = 2M + 3/2O₂

The expression for Gibbs energy is:

ΔGrxn = ∑Gproducts - ∑Greactants

Where

M₂O₃ = -6.7 kJ/mol

M = 0

O₂ = 0

$deltaG_{rxn} =((2*0)+(3/2*0))-(1*(-6.7))=6.7kJ/mol$

b) To calculate the constant we have the following expression:

$lnK=-\frac{deltaG_{rxn} }{RT}$

Where

ΔGrxn = 6.7 kJ/mol = 6700 J/mol

T = 298 K

R = 8.314 J/mol K

$lnK=-\frac{6700}{8.314*298} =-2.704\\K=0.066$

c) The equilibrium pressure of O₂ over M is:

$K=P_{O2} ^{3/2} \\P_{O2}=K^{2/3} =0.066^{2/3} =0.16atm$

3 0

2 years ago