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vredina [299]
3 years ago
10

A graduated cylinder had 20mL of water. A sample of pyrite was placed in the cylinder and the volume moved to 35 mL. What is the

volume of the pyrite?
Chemistry
1 answer:
Ksju [112]3 years ago
4 0
15mL because if it started as 20 mL and went to 35mL when u put in pyrite, the pyrite takes up 15mL
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Give the % composition for each element found in tin (IV) nitride.
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32.3699% Tin (Sn)

15.2774% Nitrogen (N)

52.3527% Oxygen (O)

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If an atom or ion has an atomic number of 3, 2 electrons, and the electronic configuration is 2, what is the mass number? ​
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It’s mass number would be 5 as it’s the protons and the neutrons added together
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When the temperature of a sample of neon gas increases, what else increases? Distance between the atoms Kinetic energy of the at
Allushta [10]

Answer: Kinetic Energy of the atoms also increases.

Explanation: We are given that the temperature of the gas increases.

Relation between kinetic energy and temperature follows:

K.E._({avg})=\frac{3RT}{2N_A}

where, K = Average Kinetic energy

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T = Temperature

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As seen from the relation above, the Kinetic energy of the gas is directly proportional to the temperature, hence as the temperature increases, kinetic energy of the atom also increases.

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Consider the nuclear equation below. 239/94 Pu—-> X+ 4/2 He. What is X?
Anna007 [38]

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What factors affect the dynamic state of equilibrium in a chemical reaction and how?
yanalaym [24]

Answer:

Only changes in temperature will influence the equilibrium constant K_c. The system will shift in response to certain external shocks. At the new equilibrium Q will still be equal to K_c, but the final concentrations will be different.

The question is asking for sources of the shocks that will influence the value of Q. For most reversible reactions:

  • External changes in the relative concentration of the products and reactants.

For some reversible reactions that involve gases:

  • Changes in pressure due to volume changes.

Catalysts do not influence the value of Q. See explanation.

Explanation:

\displaystyle K_c = {e}^{\Delta G/(R\cdot T)}.

Similar to the rate constant, the equilibrium constant K_c depends only on:

  • \Delta G the standard Gibbs energy change of the reaction, and
  • T the absolute temperature (in degrees Kelvins.)

The reversible reaction is in a dynamic equilibrium when the rate of the forward reaction is equal to the rate of the backward reaction. Reactants are constantly converted to products; products are constantly converted back to reactants. However, at equilibrium Q = K_c the two processes balance each other. The concentration of each species will stay the same.

Factors that alter the rate of one reaction more than the other will disrupt the equilibrium. These factors shall change the rate of successful collisions and hence the reaction rate.

  • Changes in concentration influence the number of particles per unit space.
  • Changes in temperature influence both the rate of collision and the percentage of particles with sufficient energy of reaction.

For reactions that involve gases,

  • Changing the volume of the container will change the concentration of gases and change the reaction rate.

However, there are cases where the number of gases particles on the reactant side and the product side are equal. Rates of the forward and backward reaction will change by the same extent. In such cases, there will not be a change in the final concentrations. Similarly, catalysts change the two rates by the same extent and will not change the final concentrations. Adding noble gases will also change the pressure. However, concentrations stay the same and the equilibrium position will not change.

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