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KiRa [710]
3 years ago
8

You have two cups one is 6cm and other 10cm with no measurement and you have to pour 8cm of water into the 10cm cup using the tw

o cup, without measuring it. How can you?
Chemistry
1 answer:
Korolek [52]3 years ago
5 0

Here’s one way to do it.

1. Fill the 6 cm cup.

2. Pour its contents into the 10 cm cup. This leaves 4 cm yet to be filled.

3. Refill the 6 cm cup and use it to fill the 10 cm cup. This leaves 2 cm in the 6 cm cup.

4. Empty the 10 cm cup and add the 2 cm from the 6 cm cup.

5. Refill the 6 cm cup.

6. Pour its contents into the 10 cm cup.

The 10 cm cup now contains 8 cm of water.

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13. How many electrons are transferred in the following reaction? (The reaction is unbalanced.) Fe(s) + I'(aq) 12(s) + Fe3+(aq)
Nat2105 [25]

Answer : The correct option is, (C) 6

Explanation :

Oxidation-reduction reaction : It is a reaction in which oxidation and reduction reaction occur simultaneously.

Oxidation reaction : It is the reaction in which a substance looses its electrons. In this oxidation state increases.

Reduction reaction : It is the reaction in which a substance gains electrons. In this oxidation state decreases.

The given unbalanced chemical reaction is,

Fe(s)+I^-(aq)\rightarrow I_2(s)+Fe^{3+}(aq)

Half reactions of oxidation and reduction are :

Oxidation : Fe(s)\rightarrow Fe^{3+}+3e^-        ......(1)

Reduction : 2I^-(aq)+2e^-\rightarrow I_2         .......(2)

In order to balance the electrons, we multiply equation 1 by 2 and equation 2 by 3, we get:

Oxidation : 2Fe(s)\rightarrow 2Fe^{3+}+6e^-        ......(1)

Reduction : 6I^-(aq)+6e^-\rightarrow 3I_2         .......(2)

The overall balanced chemical reaction will be:

2Fe(s)+6I^-(aq)\rightarrow 3I_2(s)+2Fe^{3+}(aq)

From this reaction we conclude that the electrons are getting transferred from iron to iodine and the number of electrons transferred are 6 electrons.

Hence, the correct option is, (C) 6

5 0
3 years ago
Calculate the molarity of (3.25 mol of LiCl in 2.78 L solution
alisha [4.7K]

\text{Morality}= \dfrac{\text{Number of moles}}{\text{Volume}}=\dfrac{3.25}{2.78}=1.169 ~mol/L

8 0
2 years ago
4
matrenka [14]

Answer:

Yes.

Explanation:

Yes, this difference of readings will definitely affect the results of the experiment as well as the E values because the readings taken by both students are different from one another. There is a fault in one of the thermometer because both shows different readings of temperature of the same solution. This will affect the overall experiment and due to this error, we are unable to tell that which one reading is correct so the answer is uncertain or unsure.

5 0
2 years ago
An unknown triprotic acid (H3A) is titrated with NaOH. After the titration Ka1 is determined to be 0.0013 and Ka2 is determined
e-lub [12.9K]

Answer:

6.68 X 10^-11

Explanation:

From the second Ka, you can calculate pKa = -log (Ka2) = 6.187

The pH at the second equivalence point (8.181) will be the average of pKa2  and pKa3. So,

8.181 = (6.187 + pKa3) / 2

Solving gives pKa3 = 10.175, and Ka3 = 10^-pKa3 = 6.68 X 10^-11

7 0
3 years ago
What type of bond is present between two atoms of tungsten in a light bulb filament?
stiks02 [169]

Answer:

ionic bonding

Explanation:

hope it helps

8 0
3 years ago
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