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antoniya [11.8K]
3 years ago
12

How do you prepare 1 liter of a 0.5 molar glucose solution?

Chemistry
1 answer:
riadik2000 [5.3K]3 years ago
6 0
Answer: 90 grams

0.5 molar of glucose means 0.5mole glucose for 1 liter of water. Since we want to made 1L of solution, then the amount of glucose needed is: 0.5mole/l x 1l= = 0.5mole

Glucose molecular weight is 180, then 0,5 mol of glucose is= 0.5mole x 180 grams/mole= 90 grams.
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20 points and brainliest for best answer
RSB [31]
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196.96657 u ± 0.000004 u

Potassium/Atomic mass

39.0983 u ± 0.0001 u

Francium/Atomic number

87

Copper/Atomic mass

63.546 u ± 0.003 u


Bromine/Atomic mass

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Arsenic/Atomic number

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7 0
3 years ago
Read 2 more answers
A 25.0 mL sample of a saturated C a ( O H ) 2 solution is titrated with 0.029 M H C l , and the equivalence point is reached aft
Gnesinka [82]

Answer:

0.043 M

Explanation:

The reaction that takes place is:

  • Ca(OH)₂ + 2HCl → CaCl₂ + 2H₂O

First we <u>calculate how many HCl moles reacted</u>, using the <em>given concentration and volume required to reach the equivalence point</em>:

  • 0.029 M HCl * 37.3 mL = 1.0817 mmol HCl = 1.0817 mmol H⁺

As 1 mol of H⁺ reacts with 1 mol of OH⁻, in the 25.0 mL of the Ca(OH)₂ sample there are 1.0817 mmoles of OH⁻.

With that in mind we can <u>calculate the hydroxide ion concentration in the original sample solution</u>, using <em>the calculated number of moles and given volume</em>:

  • 1.0817 mmol OH⁻ / 25.0 mL = 0.043 M
3 0
3 years ago
Intermolecular forces exist between what?
Paraphin [41]

Answer:

Intramolecular forces are the forces that hold atoms together within a molecule. Intermolecular forces are forces that exist between molecules.

Explanation:

6 0
3 years ago
Sucrose is very soluble in water. at 25◦c, 211.4 grams of sucrose will dissolve in 100 g of water. given that the density of the
stiv31 [10]
Molarity of solution is mathematically expressed as,
M = \frac{x\text{weight of solute(g)}}{\text{Molecular weight X Volume of solution(l)}}

We know that volume = mass/density
Given: mass of solution = 100 g, Density = 1.34 g/ml
∴ volume = 100/1.34 = 88.49 ml = 0.08849 l

Also, we know that molecular weight of sucrose = 342.3 g/mol
 ∴M = \frac{x\text{211.4}}{\text{342.3 X 0.08849}}
       = 6.979 M

Thus, molarity of solution is 6.979 M
8 0
2 years ago
For all of the following questions 20.00 mL of 0.200 M HBr is titrated with 0.200 M KOH.
HACTEHA [7]

Answer :

The concentration of H^+ before any titrant added to our starting material is 0.200 M.

The pH based on this H^+ ion concentration is 0.698

Explanation :

First we have to calculate the concentration of H^+ before any titrant is added to our starting material.

As we are given:

Concentration of HBr = 0.200 M

As we know that the HBr is a strong acid that dissociates complete to give hydrogen ion H^+ and bromide ion Br^-.

As, 1 M of HBr dissociates to give 1 M of H^+

So, 0.200 M of HBr dissociates to give 0.200 M of H^+

Thus, the concentration of H^+ before any titrant added to our starting material is 0.200 M.

Now we have to calculate the pH based on this H^+ ion concentration.

pH : It is defined as the negative logarithm of hydrogen ion concentration.

pH=-\log [H^+]

pH=-\log (0.200)

pH=0.698

Thus, the pH based on this H^+ ion concentration is 0.698

3 0
3 years ago
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