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antoniya [11.8K]
3 years ago
12

How do you prepare 1 liter of a 0.5 molar glucose solution?

Chemistry
1 answer:
riadik2000 [5.3K]3 years ago
6 0
Answer: 90 grams

0.5 molar of glucose means 0.5mole glucose for 1 liter of water. Since we want to made 1L of solution, then the amount of glucose needed is: 0.5mole/l x 1l= = 0.5mole

Glucose molecular weight is 180, then 0,5 mol of glucose is= 0.5mole x 180 grams/mole= 90 grams.
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Es un cambio natural o provocado, donde se produce energía para agua y dióxido de carbono: a)Precipitación. b)Fermentación c) Ef
Andre45 [30]

Answer:

d) Combustión.

Explanation:

¡Hola!

En este caso, dado que estamos enfocados en el concepto de cambio químico, el cual se caracteriza por exhibir un cambio en la composición e identidad de las sustancias iniciales (reactivos) a otras finales (productos).

Ahora bien, como se nos dice que los productos de este cambio químico son energía, agua y dióxido de carbono, inferimos que el nombre de este proceso es d) Combustión, por ejemplo la combustion del gas natural para calentar nuestras comidas en la cocina.

¡Saludos!

6 0
3 years ago
What’s the distance from the nucleus of an atom to its theoretical outer edge of electron orbits
ollegr [7]

Answer:

The range of atoms = (30-300 pm) depending upon the element

Explanation:

The Atomic radii of the atom is the distance from the center of the circle to the outermost orbital.

The center of the circle is the nucleus and the radii is the outermost boundary.

The actual size of the atom is decided on the basis of the Zeff . Also known as <em>effective nuclear charge.</em>

<em>Zeff: It is the net positive charge felt by the outermost electron by the nucleus.</em>

<em>The value of Zeff depends upon the shielding constant. More the shielding less will be the Zeff . Hence the size of the atom increases.</em>

Due to shielding the outermost electrons feel less pull of nucleus.

<em>The greater the Zeff , the smaller the radius of the atom.</em>

The formula used to calculate the atomic mass is :

r_{n}=\frac{52.9n^{2}}{Z}pm

Here "pm"= picometers

1 pm = 10^{-12}m

<u>The size of the smallest atom H-atom = 120 pm</u>

<u>The range of atoms = (30-300 pm)</u>

4 0
2 years ago
1.12g H2 is allowed to react with 9.60 g N2, producing 1.23 g NH3.
andriy [413]

Answer:

A. m_{NH_3}^{theo} =1.50gNH_3

B. Y=82.2\%

Explanation:

Hello!

In this case, since the undergoing chemical reaction between nitrogen and hydrogen is:

N_2+3H_2\rightarrow 2NH_3

Thus we proceed as follows:

A. Here, we first need to compute the moles of ammonia yielded by each reactant, in order to identify the limiting one:

n_{NH_3}^{by \ H_2}=1.12gH_2*\frac{1molH_2}{2.02gH_2}*\frac{2molNH_3}{3molH_2}=0.370molNH_3\\\\  n_{NH_3}^{by \ N_2}=1.23gN_2*\frac{1molN_2}{28.02gN_2}*\frac{2molNH_3}{1molN_2}=0.0878molNH_3

Thus, since nitrogen yields the fewest moles of ammonia, we realize it is the limiting reactant, so the theoretical yield, in grams, of ammonia is:

m_{NH_3}^{theo}=0.0878mol*\frac{17.04gNH_3}{1molNH_3} =1.50gNH_3

B. Finally, since the actual yield of ammonia is 1.23, the percent yield turns out:

Y=\frac{1.23gNH_3}{1.50gNH_3} *100\%\\\\Y=82.2\%

Best regards!

5 0
3 years ago
Two processes are described below: Process A: rapid moving water strikes a rock on the bottom of a stream and breaks it into pie
worty [1.4K]

Answer:

both represent physical  weathering

Explanation:

7 0
3 years ago
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geniusboy [140]
<span>a. 3.1 calories in heat were released by the burning candy bar sample b. The energy value of the sample was 3.1 Cal/g c.The total caloric content of the candy bar is 232.5 Calories, derived by multiplying the total mass of the candy bar by its fuel value per gram</span>
6 0
3 years ago
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