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Aleonysh [2.5K]
3 years ago
6

What is the pattern shown by the numbers 1,3,5,7,9,1,3,5,7,9?

Chemistry
1 answer:
wolverine [178]3 years ago
3 0

Answer:

the answer is D. a repeat of odd numbers less than ten

Explanation:

its all the odd numbers less than ten in order

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What would be the pH of an H2SO4 solution if the [H+] = 4.58 x 10-5 moles/liter?
Ghella [55]

Answer: pH of an H_2SO_4 solution is 4.34

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pH=-\log [H^+]

H_2SO_4\rightarrow 2H^++SO_4^{2-}

Putting in the values:

pH=-\log[4.58\times 10^{-5}]

pH=4.34

Thus pH of an H_2SO_4 solution if the [H^+] is 4.58\times 10^{-5}] is 4.34

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Question 7
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Answer:

Check if the ions of two compounds exchange places.

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3 years ago
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The standard cell potential Ec for the reduction of silver ions with elemental copper is 0.46V at 25 degrees celsius. calculate
Cloud [144]

Answer : The \Delta G for this reaction is, -88780 J/mole.

Solution :

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Cu(s)+2Ag^+(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)

Here, magnesium (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.

The half oxidation-reduction reaction will be :

Oxidation : Cu\rightarrow Cu^{2+}+2e^-

Reduction : 2Ag^++2e^-\rightarrow 2Ag

Now we have to calculate the Gibbs free energy.

Formula used :

\Delta G^o=-nFE^o

where,

\Delta G^o = Gibbs free energy = ?

n = number of electrons to balance the reaction = 2

F = Faraday constant = 96500 C/mole

E^o = standard e.m.f of cell = 0.46 V

Now put all the given values in this formula, we get the Gibbs free energy.

\Delta G^o=-(2\times 96500\times 0.46)=-88780J/mole

Therefore, the \Delta G for this reaction is, -88780 J/mole.

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It is translational motion. i know because i found it on this site. its verified too, have a nice day
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