Answer:
21.5 g.
Explanation:
Hello!
In this case, since the reaction between the given compounds is:
We can see that according to the law of conservation of mass, which states that matter is neither created nor destroyed during a chemical reaction, the total mass of products equals the total mass of reactants based on the stoichiometric proportions; in such a way, we first need to compute the reacted moles of Li3P as shown below:
Now, the moles of Li3P consumed by 15 g of Al2O3:
Thus, we infer that just 0.29 moles of 0.73 react to form products; which means that the mass of formed products is:
Therefore, the total mass of products is:
Which is not the same to the reactants (53 g) because there is an excess of Li₃P.
Best Regards!
@pandamille help her please!!!!
Method:
1) Find the atomic number in a periodic table: the number of electrons equal the atomic number
2) Use Aufbau rule
Element atomic number electron configuration
<span>
P 15 1s2 2s2 2p6 3s2 3p3
Ca 20 </span><span><span>1s2 2s2 2p6 3s2 3p6 4s2
</span>Si 14</span><span> 1s2 2s2 2p6 3s2 3p2
S 16</span><span><span> 1s2 2s2 2p6 3s2 3p4
</span>Ga 31. </span><span><span> 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p</span> </span>
Explanation:
Atomic number of magnesium is 12 and its electronic distribution is 2, 8, 2. On the other hand, atomic number of iodine is 53 and its electronic configuration is ![[Kr]4d^{10}5s^{2}5p^{5}](https://tex.z-dn.net/?f=%5BKr%5D4d%5E%7B10%7D5s%5E%7B2%7D5p%5E%7B5%7D)
.
Hence, there are 7 valence electrons in an iodine atom and there are 2 valence electrons in a magnesium atom.
So, one atom of iodine requires one electron from a donor atom to complete its octet. But one magnesium atom contains two valence electrons.
Therefore, one magnesium atom will combine with two iodine atoms to result in the formation of magnesium iodide as follows.
Therefore, an ionic bond will be formed when magnesium reacts with iodine to make magnesium iodide.
1.T
2.F
3.T
I think I think Im not complety sure sorry
