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natta225 [31]
3 years ago
13

A gas sample occupies 3.25 liters at 297.5K and 2.4 atm. Determine the temperature at which the gas will occupy 4.25 L at 1.50 a

tm.
Chemistry
1 answer:
lorasvet [3.4K]3 years ago
7 0

For equal moles of  gas, temperature can be calculated from ideal gas equation as follows:

P×V=n×R×T ...... (1)

Initial volume, temperature and pressure of gas is 3.25 L, 297.5 K and 2.4 atm respectively.

2.4 atm ×3.25 L=n×R×297.5 K

Rearranging,

n\times R=0.0262 atm L/K

Similarly at final pressure and volume from equation (1),

1.5 atm ×4.25 L=n×R×T

Putting the value of n×R in above equation,

1.5 atm ×4.25 L=0.0262 (atm L/K)×T

Thus, T=243.32 K


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At a certain temperature, a mixture of 2 gases, 11.2 g of oxygen and 104.75 of krypton exert a total pressure of 4.25 atm. What
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Answer:

Pressure of O₂ = 0.93 atm

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Explanation:

This problem can be solved by using Dalton's Law of Partial Pressures, which states that the partial pressure of a component of a gaseous mixture depends on the mole ratio of said component and the total pressure of the gaseous mixture.

Pₐ = Xₐ * Ptotal

P ₐ  - the partial pressure of component  a  

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The moles of the two gases are:

moles of O₂ = 11.2/32 = 0.35 moles

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Pressure of O₂ = 0.35/1.6 *4.25 = 0.93 moles

Pressure of krypton = 1.25/1.6 *4.25 = 3.32 moles

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