Answer:
D. TA < TB
Explanation:
From general gas equation, we know that:
PV = nRT
PV/R = nT
where,
P = pressure of gas
V = volume of gas
R = General gas constant
T = temperature of gas
n = no. of moles of gas
<u>FOR CYLINDER A</u>:
PV/R = (nA)(TA) _____ eqn (1)
<u>FOR CYLINDER B</u>:
PV/R = (nB)(TB) _____ eqn (2)
Because, Pressure, Volume are constant for both cylinders.
Comparing eqn (1) and (2)
(nA)(TA) = (nB)(TB)
It is given that the amount of gas in cylinder A is twice as much as the gas in cylinder B. This means the number moles in cylinder A are twice as much as no. of moles in cylinder B.
nA = 2(nB)
using this in eqn:
2(nB)(TA) = (nB)(TB)
TA = (1/2)(TB)
<u>TA = 0.5 TB</u>
Therefore it is clear that the correct option is:
<u>D. TA<TB</u>
The work done by the friction force to stop the player is equal to his loss of kinetic energy:

The work done by the friction force is the magnitude of the force

times the distance covered by the player, d:

The loss in kinetic energy is simply equal to the initial kinetic energy of the player, since the final kinetic energy is zero (the player comes to rest):

Substituting into the first equation, we get:

from which we find d, the distance covered by the player:
Answer:
Explanation:
1) ½(0.8)t² = 4t
0.4t² = 4t
0.4t = 4
t = 10 s
2) d = vt = 4(10) = 40 m
d = ½atⁿ = ½(0.8)10² = 40 m
3) v = at = 0.8(10) = 8 m/s