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tatiyna
3 years ago
9

How high is the average telephone pole

Physics
2 answers:
kenny6666 [7]3 years ago
7 0

The average telephone pole stands about 40ft in the air.

Ksivusya [100]3 years ago
7 0

Well the first dude isn't wrong it is 40ft....But it's taller than me

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When hydrogen is heated or subjected to an electric discharge, it emits light with specific visible wavelengths. A diffraction g
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d sin\theta = m\lambda

Here,

d = Distance between Slits

m = Order of the fringes

\lambda = Wavelength

\text{Spacing between adjacent lines} = d = 4926nm

\text{Wavelength of light} = \lambda = 656nm

Rearranging to find the angle,

sin\theta = \frac{m\lambda}{d}

\theta = sin^{-1}(\frac{m\lambda}{d})

\theta = sin^{-1}(\frac{(4)(656*10^{-9}m)}{4926*10^{-9}m})

\theta = 32.19\°

Therefore the angle that the fourth order bright fringe occur for this specific wavelenth of light occur is 32.19°

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If a ball is dropped from a height of 10 m, hits the ground and bounces back up to a maximum height of 7.5 m, describe how the E
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Explanation:

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An instrument that measures and detects vibrations in earth is known as a _______.
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A boom box, stereo set.
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In a high school swim competition, a student takes 1.6 s to complete 1.5 somersaults. Determine the average angular speed of the
Rufina [12.5K]

Answer:

The  angular speed is w = 5.89 \ rad/s

Explanation:

From the question we are told that

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The total angular displacement during the somersault is mathematically represented as

         \theta  =  n *  2 *  \pi

substituting values

        \theta  =  1.5 *  2 *  3.142

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 The angular speed is mathematically represented as

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substituting values

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3 years ago
A small car has a head-on collision with a large truck. Which of the following statements concerning the magnitude of the averag
andrey2020 [161]

Answer:

The small car and the truck experience the same average force.

Explanation:

Here we need to remember two of Newton's laws.

The second one says that:

F = m*a

force equals mass times acceleration.

And the third one says that;

"If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A"

From the third law, if the car experiences a force F due to the impact with the truck, then the truck experiences the same force F due to the impact.

But this seems odd, because we would expect to see the car being more affected by the impact, right?

Well, this is explained by the second law.

Suppose that the mass of the car is m, and the mass of the truck is M.

such that M > m

Then for the small car we have:

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And for the truck:

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Because the force is the same for both of them, we can write:

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because M > m, then M/m > 1.

This means that the acceleration that the car experiences is larger than the acceleration for the truck, and this is why we would see that the car seems more affected by the impact, regardless of the fact that both vehicles experience the same force in the impact.

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2 years ago
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