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tatiyna
3 years ago
9

How high is the average telephone pole

Physics
2 answers:
kenny6666 [7]3 years ago
7 0

The average telephone pole stands about 40ft in the air.

Ksivusya [100]3 years ago
7 0

Well the first dude isn't wrong it is 40ft....But it's taller than me

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Moon eclipse is when the moon interposes between the sun and behind the Earth. The moon passes behind the Earth into its umbra and not viceversa! This is possible when the three of them are ALIGNED (in syzygy). In Romania, there was such eclipse that could be seen at an October night last year.
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3 years ago
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A ball is launched at an angle of 10 degrees from a 20 meter tall building with a speed of 4 m/s. How long is the ball in the ai
shutvik [7]

Answer:

d) None of the above

Explanation:

v_{o} = inituial velocity of launch = 4 m/s

θ = angle of launch = 10 deg

Consider the motion along the vertical direction

v_{oy} = initial velocity along vertical direction = 4 Sin10 = 0.695

m/s

a_{y} = acceleration along the vertical direction = - 9.8 m/s²

y = vertical displacement = - 20 m  

t = time of travel

using the equation

y=v_{oy} t+(0.5)a_{y} t^{2}

- 20 = (0.695) t + (0.5) (- 9.8) t²

t = 2.1 sec

consider the motion along the horizontal direction

x = horizontal displacement

v_{ox} = initial velocity along horizontal direction = 4 Cos10 = 3.94 m/s

a_{x} = acceleration along the horizontal direction = 0 m/s²

t = time of travel =  2.1 s

Using the kinematics equation

x =v_{ox} t+(0.5)a_{x} t^{2}

x = (3.94) (2.1) + (0.5) (0) (2.1)²

x = 8.3 m

Consider the motion along the vertical direction

v_{oy} = initial velocity along vertical direction = 4 Sin10 = 0.695

m/s

a_{y} = acceleration along the vertical direction = - 9.8 m/s²

y_{o} =initial vertical position at the time of launch = 20 m  

y = vertical position at the maximum height = 20 m

v_{fy} = final velocity along vertical direction at highest point = 0 m/s

using the equation

{v_{fy}}^{2}= {v_{oy}}^{2} + 2 a_{y}(y - y_{o})

0^{2}= 0.695^{2} + 2 (- 9.8)(y - 20)

y = 20.02 m

h = height above the starting height

h = y - y_{o}

h = 20.02 - 20

h = 0.02 m

7 0
3 years ago
The Skeleton does a surprising number of things. What are the three main Ones? lol, it's due today at 12:59 pm I need help.
ICE Princess25 [194]

Answer:

Support

Posture

Protection

Explanation:

Support – the skeleton keeps the body upright and provides a framework for muscle and tissue attachment.

Posture – the skeleton gives the correct shape to our body.

Protection – the bones of the skeleton protect the internal organs and reduce the risk of injury on impact.

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What are conductors and insulators? Give at least five example of each ​
Leona [35]

Answer: conductors are substances that allow heat or electricity to pass through . It deals with only the flow of electrons.

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Insulators are materials that do not allow heat or electricity to pass through.

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Explanation:

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3 years ago
7. 13 a turbine receives steam at 6 mpa, 600°c with an exit pressure of 600 kpa. Assume the turbine is adiabatic and neglect kin
AnnyKZ [126]

The work done by the turbine will be 708.2 kJ/kg. The work done by the turbine is the difference of the enthalpy at inlet and exit.

<h3 /><h3>What is temperature?</h3>

Temperature directs the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles, more the temperature.

If the given turbine is assumed to be reversible;

\rm P_I(Initial pressure)=60 mpa = 60 bar

\rm  T_i(Initial temperature)=600° C

\rm P_e (Exit pressure)=600 kpa=6 bar

The heat balance equation is;

\rm q-W_t=h_e-h_i\\\\ q=0\\\\\ W_t=h_i-h_e

The change in the entropy is;

\rm S_2-S_1=\frac{\delta q}{dt}

The work done by the turbine is;

\rm W_t = h_i-h_e\\\\ W_t =3658.4 -29.5019\\\\  W_t =708.2 \ kJ/kg

Hence,the work done by the turbine will be 708.2 kJ/kg.

To learn more about the temperature, refer to the link;

brainly.com/question/7510619

#SPJ4

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