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tatiyna
3 years ago
9

How high is the average telephone pole

Physics
2 answers:
kenny6666 [7]3 years ago
7 0

The average telephone pole stands about 40ft in the air.

Ksivusya [100]3 years ago
7 0

Well the first dude isn't wrong it is 40ft....But it's taller than me

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What is the tendency of matter to resist any change in motion?
salantis [7]

Answer: inertia

Explanation:

Inertia is the tendency of an object to resist changes in its state of motion

6 0
2 years ago
If an electromagnetic wave has components Ey = E0 sin(kx - ωt) and Bz = B0 sin(kx - ωt), in what direction is it traveling?
fomenos

Answer:

Its traveling in the +x direction

Explanation:

The E-field is in the +y-direction, and the B-field is in the +z-direction, so it must be moving along the +x-direction, since the E-field, B-field and the direction of moving are all at right angles to each other.

8 0
3 years ago
For the circuit in the previous part, with the frequency set at 1 hz, what happens if the inductance of the inductor is increase
lubasha [3.4K]
The relationship between inductance and frequency can be clearly described using the following equation of inductive reactance:

Xl = 2*pi*f*L ; simplifying:

L = Xl / 2*pi*f

Therefore, as what we saw, inductance and frequency are inversely proportional. To add up, when inductance increases the frequency would decrease.
7 0
2 years ago
What is the temperature increase of 4.0 kg of water when heated by an 800-W immersion heater for 10 min? (cw = 4 186 J/kg⋅°C)
Llana [10]

Answer:

option C

Explanation:

given,

mass of water = 4 Kg

Water is heated to = 800 W

time of immersion = 10 min

                              = 10 x 60 = 600 s

using equation of specific heat  

Q = m S ΔT

S is the specific heat capacity of water which is equal to 4182 J/kg°C.

and another formula of heat

Q = Pt

now,

P t =  m S ΔT

800 x 600  = 4 x 4182 x ΔT

ΔT = 29° C

temperature increased is equal to ΔT = 29° C

Hence, the correct answer is option C

3 0
2 years ago
The standard emf for the cell using the overall cell reaction below is +2.20 V: 2Al(s) + 3I2 (s) → 2Al3+ (aq) + 6I− (aq) The emf
Triss [41]

Answer: +2.10V

Explanation:

2Al(s)+3I_2(s)\rightarrow 2Al^{3+}(aq)+6I^-(aq)

Using Nernst equation :

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log K

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log [Al^{3+}]^2\times [I^-]^6

where,

E^o_{cell} = standard emf for the cell = +2.20 V

n = number of electrons in oxidation-reduction reaction = 6

E_{cell} = emf of the cell = ?

[Al^{3+}]  = concentration = 5.0\times 10^{-3}M

[I}^{-}]  = concentration = 0.10M

Now put all the given values in the above equation, we get:

E_{cell}=+2.20-\frac{0.059}{6}\log [5.0\times 10^{-3}]^2\times [0.10]^6

E_{cell}=2.10V

The standard emf for the cell using the overall cell reaction below is +2.10 V

5 0
3 years ago
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