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Ivan
4 years ago
11

When a phasor-domain circuit has dependent sources, you should not use a sequence of source transforms to find the thévenin and

norton equivalents for that circuit, and you cannot use the equivalent impedance technique to find the equivalent impedance. instead, you must find the open-circuit phasor voltage (which is the thévenin voltage) and the short-circuit phasor current (which is the norton current). then you can use ohm's law with the phasor voltage and current to find the thévenin (or norton) impedance. remember that you can also use the test source method to find the thévenin impedance. consider the circuit shown here. in this circuit, the phasor voltage source vs=10∠0∘ v. we wish to find the norton equivalent of this circuit to the left of terminals a and
b?
Chemistry
1 answer:
GrogVix [38]4 years ago
6 0
Yes but the answer is A

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How do I do this whole problem?
KatRina [158]

The solubility of a substance in water is dependent on the temperature. Thus for

1 & 2: Temperature is the independent variable (the one that changes in the first place) and Solubility is a dependent variable (a variable that changes in response to changes in the independent variable.)

The graph: by convention you shall label the horizontal axis with the independent variable and the vertical axis with the dependent variable. For clarity's sake you shall use the finest scale possible that accommodates for all data provided for both axis. Plot the data points on the graph as if they are points on a cartesian plane.

My teacher made no detailed requirements on the phrasing on titles of solubility curve plots; however, like most other graphs in chemistry, the title shall specify the name of variables presented in this visualization. For instance, "the solubility of KClO_3 under different temperatures" might do. You shall refer to your textbooks for such convention.

It is necessary to interpolate to find the solubility at a temperature not given in the table. Start by connecting all given data points with a smooth line; find the vertical line corresponding to temperature = 75 degree Celsius and determine the solubility at the intersection of the vertical line and the trend line. That point shall approximates the solubility of the salt at that temperature.

4 0
4 years ago
What is the balanced equation for CaCO3(s) > CaO(s) + CO2(g
vlada-n [284]
Balanced equation :

1 CaCO3(s) = 1 CaO(s) + 1 CO2(g)

hope this helps!

3 0
3 years ago
Help for extra credit
katen-ka-za [31]
Why not search it up and figure it out and then write it how you would?
6 0
3 years ago
Convert 732.0 mmHg to atm
enot [183]

Answer:

The answer is

<h2>0.95 atm</h2>

Explanation:

To solve the question we use the following conversion

That's

1 mmHg \cong 0.0013 atm

So we have

If 1 mmHg \cong 0.0013 atm

Then 732 mmHg will be

732 × 0.0013 atm

We have the final answer as

<h3>0.95 atm</h3>

Hope this helps you

5 0
4 years ago
Two gas-containers, A and B, are connected with a valve. The first container, A, has a volume of 135 mL, and the second containe
stiv31 [10]

Answer:

85.5 mmHg is the pressure of the gas sample when the valve is opened.

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas in container A = 165 mmHg

P_2 = final pressure of gas = ?

V_1 = initial volume of gas in container A= 135 mL

V_2 = final volume of gas = 135 mL + 117 mL = 252 mL

T_1 = initial temperature of gas in container A = 22.5^oC=273+22.5=295.5 K

T_2 = final temperature of gas = 12.7^oC=273+12.7=285.7K

Now put all the given values in the above equation, we get:

P_2=\frac{P_1V_1\times T_2}{T_1\times V_2}

=\frac{165 mmHg\times 135 mL\times 285.7 K}{295.5 K\times 252 mL}

P_2=85.5 mmHg

85.5 mmHg is the pressure of the gas sample when the valve is opened.

8 0
4 years ago
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