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Ad libitum [116K]
3 years ago
13

ﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺ

ﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺ

Chemistry
2 answers:
ddd [48]3 years ago
4 0
What is this????????????
Fofino [41]3 years ago
3 0

Answer: What do you need help with?

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Magnesium metal reacts with iodine gas at high temperatures to form magnesium iodide. what mass of mgi2 can be produced from the
sergiy2304 [10]
<span>54.8 g of MgI2 can be produced. To solve this, you need to determine the molar mass of each reactant and the product. First, look up the atomic weights of iodine and magnesium Atomic weight of Iodine = 126.90447 Atomic weight of Magnesium = 24.305 Molar mass of MgI2 = 24.305 + 2 * 126.90447 = 278.11394 Now determine how many moles of Iodine and Magnesium you have moles of Iodine = 50.0 g / 126.90447 g/mol = 0.393997154 mole moles of Magnesium = 5.15 / 24.305 g/mol = 0.211890557 mole Since for every magnesium atom, you need 2 iodine atoms and since the number of moles of available iodine isn't at least 2 times the available moles of magnesium, iodine is the limiting reagent. So figure out how many moles of magnesium will be consumed by the iodine 0.393997154 mole / 2 = 0.196998577 mole. This means that you can make 0.196998577 moles of MgI2. Now simply multiply by the previously calculated molar mass of MgI2 0.196998577 mole * 278.11394 g/mole = 54.78805 g Round the result to the correct number of significant figures. 54.78805 g = 54.8 g</span>
5 0
3 years ago
How many grams of a 22.9% sugar solution contain 68.5 g of sugar?
777dan777 [17]

    The grams  of 22.9 %   sugar  solution that contain 68.5  g  of   sugar  is 299.13 g  of  solution  

   <u><em>calculation</em></u>

 22.9%  means that  there are  22.9 g  of  sugar  in 100 g of solution.

   what about   68.5 g  of sugar

- <em>by cross    multiplication</em>

=[(68.5 g  sugar x 100  g  solution) /22.9  g sugar] =299.13 g  of solution

Nb; <em>g sugar cancel  each other</em>

5 0
3 years ago
Hi GUYS PLEASE HELP ME YOU KNOW I HELP YOU WHEN YOU NEED IT MOST SO HERE IT GOES WHICH SEQUENCE REPRESENTS THE ORDER OF DEVELOPM
exis [7]
To answer your question, the answer is number 1. hope this help
6 0
3 years ago
List the substances Ar, Cl2, CH4, and CH3COOH, in order of increasing strength of intermolecular attractions. List the substance
Viefleur [7K]

Answer:

Order of increasing strength of intermolecular attraction:

CH_3COOH > Cl_2 > CH_4 > Ar

Explanation:

CH_3COOH can form hydrogen bond as H atom is attached with electronegative atom O.

Rest three, Cl_2,  CH_4,  Ar are non-polar molecules.

In non-polar molecules, van der Waal's intermolecular forces of attractions exist. Hydrogen bonding is stronger intermolecular attraction then van der Waal's intermolecular forces of attraction, hence, CH_3COOH has strongest intermolecular attractions.

Ar will have least intermolecular attraction, as it behaves almost as ideal gas and there is no intermolecular attraction exist between molecules of ideal gases.

Molecular size and mass of Cl_2 is high as compared to CH_4.

van der Waals intermolecular forces of attraction increases with increase in size.

Therefore,

Order of increasing strength of intermolecular attraction will be:

CH_3COOH > Cl_2 > CH_4 > Ar

8 0
3 years ago
Read 2 more answers
A lab technician mixed a 550 ml solution of water and alcohol. if​ 3% of the solution is​ alcohol, how many milliliters of alcoh
kupik [55]

The solution 550 ml total and first we will find the amount of alcohol. 3% = 0.03 550 ml x .03 = 16.5 ml alcohol
 Then to find the amount of water used, we just have to subtract the amount of alcohol from the total volume  
550 ml total - 16.5 ml alcohol = 533.5 ml water
5 0
3 years ago
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