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Ad libitum [116K]
3 years ago
13

ﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺ

ﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺ

Chemistry
2 answers:
ddd [48]3 years ago
4 0
What is this????????????
Fofino [41]3 years ago
3 0

Answer: What do you need help with?

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Which factor is generally responsible for high melting points?
kherson [118]
The factor that is generally responsible for higher melting point is intermolecular forces. The compounds that are covalent in nature are made of molecules rather than ions. It has been seen that some of the covalent compounds have polar molecules at one end, due to which the one end has more electronegative force than the other. The electrostatic force that is bounding the compound is the main cause of higher melting point of this compound.  So it is true that with the increase of polarity of a compound creates higher melting point. .. hope I helped
3 0
3 years ago
A student ran the following reaction in the laboratory at 671 K: 2NH3(g) N2(g) + 3H2(g) When she introduced 7.33×10-2 moles of N
vaieri [72.5K]

Answer:

Kc = 8.05x10⁻³

Explanation:

This is the equilibrium:

                 2NH₃(g)   ⇄     N₂(g)     +     3H₂(g)

Initially       0.0733

React         0.0733α          α/2                3/2α

Eq     0.0733 - 0.0733α    α/2                0.103

We introduced 0.0733 moles of ammonia, initially. So in the reaction "α" amount react, as the ratio is 2:1, and 2:3, we can know the moles that formed products.

Now we were told that in equilibrum we have a [H₂] of 0.103, so this data can help us to calculate α.

3/2α = 0.103

α = 0.103 . 2/3 ⇒ 0.0686

So, concentration in equilibrium are

NH₃ = 0.0733 - 0.0733 . 0.0686 = 0.0682

N₂ = 0.0686/2 = 0.0343

So this moles, are in a volume of 1L, so they are molar concentrations.

Let's make Kc expression:

Kc= [N₂] . [H₂]³ / [NH₃]²

Kc = 0.0343 . 0.103³ / 0.0682² = 8.05x10⁻³

3 0
3 years ago
If a frog initially contained 2 grams of carbon-14 and the half-life of carbon-14 is 5,730 years, how much carbon-14 remains in
andreyandreev [35.5K]
Half life is the time taken for a radioactive isotope to decay by half its original mass. In this case the half life of carbon-14 is 5.730 years. 
Using the formula;
New mass = original mass × (1/2)^n; where n is the number of half lives (in this case n=1 ) 
New mass = 2 g × (1/2)^1     
                  = 1 g
Therefore; the mass of carbon-14 that remains will be 1 g 
5 0
3 years ago
If a liquid sample of naphthalene is heated and remains at 218 degrees c until it is completely vaporized, you know that 218 deg
Alexxandr [17]
<span>The correct answer is b. Boiling point, why? because the liquid sample of napthalene is heated and remained at the temperature of 218 degrees celsius, the outcome was that the napthalene was completely vaporized, therefore we are given the scenario that at the temperature of 218 degrees celsius is considered to be the boiling pont of napthalene.</span>
5 0
3 years ago
Read 2 more answers
Which element most likely has the same number of valence electrons as silicon(si)?
Blizzard [7]

Answer:

Carbon, germanium, tin and lead.

Explanation:

The silicon is belong to the carbon family. There are five elements in carbon family carbon, silicon, germanium, tin and lead. These five elements are present in same group i.e group fourteen. The elements present in same group have same number of valance electrons.

For example.

Carbon electronic configuration:

C₆ = [He]  2s² 2p²

Silicon electronic configuration:

Si₁₄ = [Ne] 3s² 3p²

Germanium electronic configuration:

Ge₃₂ = [Ar] 3d¹⁰ 4s² 4p²

Tin electronic configuration:

Sn₅₀ = [Kr] 4d¹⁰ 5s² 5p²

Lead electronic configuration:

Pb₈₂ = [Xe] 4f¹⁴ 5d¹⁰ 6s² 6p²

we can see that in case of all elements there are four valance electrons, which are equal to the valance electrons of silicon.

7 0
3 years ago
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