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Ad libitum [116K]
3 years ago
13

ﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺ

ﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺﷺ

Chemistry
2 answers:
ddd [48]3 years ago
4 0
What is this????????????
Fofino [41]3 years ago
3 0

Answer: What do you need help with?

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Devante buys a helium birthday balloon for his mom at the grocery store, where the temperature is a comfortable 72oF. He takes t
frozen [14]
The balloon would be smaller and not float as well because of the low temperature. The particles in the balloon when in the car will slow down and get closer together because of the low temperature. That caused it to become more dense and smaller in size then before. When in the store, the particulars in the balloon we’re moving faster and more spread apart
5 0
3 years ago
Thermal energy is transferred from?
aliina [53]

Answer:

chemical and electrical ( and sometimes nucelar)

Explanation:

4 0
3 years ago
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Help this is due soon!!!
denis23 [38]

Answer:

not 100% sure but I think it's unbalanced chemical

6 0
3 years ago
Dilute 0.407M & 2.56L solution to 7.005L. CF?
Alenkinab [10]

Answer:

C₂ = 0.149 M

Explanation:

Given data:

Initial concentration = 0.407 M

Initial volume = 2.56 L

Final volume = 7.005 L

Final concentration = ?

Solution:

Formula:

C₁V₁ = C₂V₂

C₁ = Initial concentration

V₁ = Initial volume

C₂ = Final concentration

V₂ =Final volume

Now we will put the values.

0.407 M × 2.56 L =  C₂ × 7.005 L

1.042 =  C₂ × 7.005 L

C₂ = 1.042 M.L / 7.005 L

C₂ = 0.149 M

5 0
3 years ago
How many moles of Ca(OH)2 are in 3.5kg of Ca(OH)2? Answer in units of mole
Kobotan [32]
First, you need to convert kg to g. 
So, 1 kg =1000g.
3.5 x 1000 = 3500g Ca(OH)2

We need to know the molar mass of Ca(OH)2. 
Ca= 40.08 g
O=2(15.999)
H=2(1.0079)

Add them all together and you get 74.0938 g.

Put it in the formula from mass to moles. 

# of moles = grams Ca(OH)2 x 1 mol Ca(OH)2
                                                  --------------------
                                                  molar mass Ca(OH)2

3500 g Ca(OH)2 x 1 mol Ca(OH)2
                              ---------------------
                             74.0938 g Ca(OH)2

So divide 1/74.0938 and multiply by 3500.

You will get about 47.24 moles Ca(OH)2.

Hope this helps! :)
7 0
3 years ago
Read 2 more answers
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