Explanation:
Given that,
The frequency of electromagnetic spectrum is 
(A) Let the wavelength of this radiation is
. We know that,

So, the wavelength of this radiation is
.
(B) Let E is the energy associated with this radiation. Energy of an electromagnetic radiation is given by :

h is Planck's constant

1 kcal = 4184 J
It means,

Hence, this is the required solution.
Answer:
<h2>Which of the following statements correctly describes a difference between mechanical waves and electromagnetic waves?</h2><h2><em>
:- Mechanical waves require a medium to travel through, whereas electromagnetic waves can travel through empty space.</em></h2>
<em>is the correct</em>
<em>pls mark me as brainliest pls </em>
<em></em>
<h3 />
Answer:
Compound.
Explanation:
That would be compound as it consists of a number of elements bonded together. It is inorganic not organic.
Answer:
10043.225 J
Explanation:
We'll begin by calculating the amount of heat needed to change ice to water since water at 0°C is ice. This is illustrated below:
Mass (m) = 15.5g
Latent heat of fussion of water (L) = 334J/g
Heat (Q1) =..?
Q1 = mL
Q1 = 15.5 x 334
Q1 = 5177 J
Next, we shall calculate the amount of heat needed to raise the temperature of water from 0°C to 75°C.
This is illustrated below:
Mass = 15.5g
Initial temperature (T1) = 0°C
Final temperature (T2) = 75°C
Change in temperature (ΔT) = T2 – T1 = 75 – 0 = 75°C
Specific heat capacity (C) of water = 4.186J/g°C
Heat (Q2) =?
Q2 = MCΔT
Q2 = 15.5 x 4.186 x 75
Q2 = 4866.225 J
The overall heat energy needed is given by:
QT = Q1 + Q2
QT = 5177 + 4866.225
QT = 10043.225 J
Therefore, the amount of energy required is 10043.225 J