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blondinia [14]
3 years ago
9

If the horizontal component of a vector is 6 m/s and the vertical component is also 6 m/s, what is the resultant value of the ve

ctor?
A. 6 m/s
B. 8.5 m/s
C. 10.4 m/s
D. 12 m/s
Physics
1 answer:
BlackZzzverrR [31]3 years ago
6 0
Resultant force= (2*6^2)^(1/2)
=8.5m/s
answer is B.
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To solve this exercise it is necessary to apply the equations related to the magnetic moment, that is, the amount of force that an image can exert on the electric currents and the torque that a magnetic field exerts on them.

The diple moment associated with an iron bar is given by,

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Where,

\alpha = Dipole momento associated with an Atom

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\alpha y previously given in the problem and its value is 2.8*10^{-23}J/T

L = 5.8cm = 5.8*10^{-2}m

A = 1.5cm^2 = 1.5*10^{-4}m^2

The number of the atoms N, can be calculated as,

N = \frac{\rho AL}{M_{mass}}*A_n

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A = Area

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N = \frac{(7.9g/cm^3)(1.5cm)(5.8cm^2)}{55.9g/mol}(6.022*10^{23}atoms/mol)

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\mu = (2.8*10^{-23})*(7.4041*10^{23})

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\tau = 45.584N.m

<em>Note: The angle generated is perpendicular, so it takes 90 ° for the calculation made.</em>

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