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lions [1.4K]
3 years ago
12

Car a runs a red light and broadsides car b, which is stopped and waiting to make a left turn. car a has a mass of 1,800kg. car

b has a mass of 1,500kg. after the impact, the cars stick together and slide away at a speed of 7.1m/s. how fast was car a going when it hit car b?
Physics
1 answer:
frez [133]3 years ago
7 0

The law of conservation of momentum tells us that momentum is conserved, therefore total initial momentum should be equal to total final momentum. In this case, we can expressed this mathematically as:

mA vA + mB vB = m v

where, m is the mass in kg, v is the velocity in m/s

since m is the total mass, m = mA + mB, we can write the equation as:

mA vA + mB vB = (mA + mB) v

furthermore, car B was at a stop signal therefore vB = 0, hence

mA vA + 0 = (mA + mB) v

1800 (vA) = (1800 + 1500) (7.1 m/s)

<span>vA = 13.02 m/s</span>

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Answer:

Explanation:

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Answer:

4 tonne/m³

Explanation:

ρ = m / V

ρ = 49 g / (π (17.4 mm / 2)² (50.3 mm))

ρ = 0.0041 g/mm³

Converting to tonnes/m³:

ρ = 0.0041 g/mm³ (1 kg / 1000 g) (1 tonne / 1000 kg) (1000 mm / m)³

ρ = 4.1 tonne/m³

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3 years ago
A bicycle rider traveling east at 10 km/hr sees a blue car pass her appearing to travel west at 50 km/hr. What is the blue car's
BigorU [14]

Answer:

v_{bR} = 25 km/h towards west

Explanation:

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v_{bc} = 50 km/h towards west

also it is given that bicycle is moving at speed of 10 km/h towards East

so here we have

v_{bc} = v_b - v_c

so we have

v_b = v_{bc} + v_c

v_b = -50 + 10 = 40 km/h towards west

now speed of the red car is given as 15 km/h towards west

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If you're going 80 mph how long does it take to go 80 miles
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1 mile. Is this a joke lol
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A train locomotive is pulling two cars of the same mass behind it. Determine the ratio of the tension in the coupling (think of
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Answer:

The ratio is  \frac{F_{T1}}{F_{T2}}  =  2

Explanation:

The diagram for this question is shown on the first uploaded image

Here we are assume the acceleration of the train is a

which makes the acceleration of each car a

From the question we are told that

      Considering the second car

 The force causing it s movement  is mathematically represented as

       F_{T2} =  ma

 Considering the first car

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      F  = F_{T1} -F_{T2} = ma

=>   F_{T1} -ma  = ma

=>   F_{T1} =  2 ma

=> \frac{F_{T1}}{ma}  =  2

=> \frac{F_{T1}}{F_{T2}}  =  2

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3 years ago
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