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Vinvika [58]
3 years ago
15

TRUE/FALSE, the scientific question is written like “I wonder if [dependent variable] is affected by [independent variable].”

Physics
1 answer:
sergiy2304 [10]3 years ago
6 0
True as the independent variable is over the dependent variable and controls it as the dependent relies on the independent.
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Two concentric conducting spherical shells produce a radially outward electric field of magnitude49,000 N/C at a point 4.10 m fr
Korolek [52]

To solve this problem it is necessary to apply the concepts related to the electric field according to the definition of Coulomb's law.

 The electric field is defined mathematically as a vector field that associates to each point in space the (electrostatic or Coulomb) force per unit of charge exerted on an infinitesimal positive test charge at rest at that point.

Mathematically this can be described as:

E = \frac{1}{4\pi \epsilon_0}\frac{q}{r^2}

Where,

\epsilon_0 = permittivity of free space

r = Distance

q = Charge

E = Electric Field

Our values are given as,

E= 49.000N/C

r= 4.1m

\epsilon_0=8.854*10{-12}C^2N^{-1}m^{-2}

Replacing we have,

E = \frac{1}{4\pi \epsilon_0}\frac{q}{r^2}

49000 = \frac{1}{4\pi (8.854*10{-12})}\frac{q}{(4.1)^2}

q= 9.16*10^{-5} C

q= 91.6\mu C

Therefore the amoun of charge on the outer surface of the larger shell is 91.6 \mu C

6 0
4 years ago
Anyone want to be f-r-i-e-n-d-s? ^^ (You may answer for fr/ee points! <3)
Nuetrik [128]

Answer:

YESSSS!

Explanation:

3 0
3 years ago
Read 2 more answers
Where would you expect the oceanic crust to be the hottest
Dimas [21]
It is the hottest at the mid ocean ridge because new crust is formed from the lava.
8 0
4 years ago
find the mass of a ball on a roof 30 meters high, if the ball's gravitational potential energy is 58.8 joules
Sidana [21]
We are given the gravitational potential energy and the height of the ball and is asked in the problem to determine the mass of the ball. the formula to be followed is PE = mgh where g is the gravitational acceleration equal to 9.81 m/s^2. substituting, 58.8 J = m*9.8 m/s^2 * 30 m; m = 0.2 kg.
3 0
3 years ago
Read 2 more answers
(a) How fast must a 3000-kg elephant move to have the same kinetic energy as a 65.0-kg sprinter running at 10.0 m/ s?
Aleksandr-060686 [28]

Answer:

1.4719 m per sec

Explanation:

Hello

Kinetic energy is the energy associated with the movement of objects. Although there are many forms of kinetic energy  

the formula to use is

E=\frac{mv^{2} }{2}

where m is the mass of the object and v the velocity

lets see the kinetic energy of the sprinter running

E=\frac{65 Kg*10(\frac{m}{s} ^)){2} }{2} \\\\E=\frac{65 *100 }{2} \\E=3250 Joules\\\\

Now, the elephant must have the same kinetic energy

E=\frac{m*v_{2} ^{2} }{2} \\\\E*2=m*v_{2} ^{2}\\ \frac{2E}{m} =v_{2} ^{2} \\\sqrt{\frac{2E}{m} } =v_{2}  \\\\\\v_{2} =\sqrt{\frac{2*3250}{3000} }\\ \\v_{2} =1.4719 \frac{m}{s} \\\\

it works only the positive root, so the elephant must to  walk  to 1.4719 m/s to have the same kinetic energy.

Have a great day

8 0
3 years ago
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