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Vinvika [58]
3 years ago
15

TRUE/FALSE, the scientific question is written like “I wonder if [dependent variable] is affected by [independent variable].”

Physics
1 answer:
sergiy2304 [10]3 years ago
6 0
True as the independent variable is over the dependent variable and controls it as the dependent relies on the independent.
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What does a physicist study?
MissTica

Answer:

A. Matter and energy

Explanation:

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Which force is represented by the arrow at A?
Nat2105 [25]

Answer:

B) Force of gravity

Explanation:

As it is the force which acts downward on the body towards the ground, it is clearly the force gravity represented by the arrow at A.

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How does the movement of particles of matter change when matter goes from solid to liquid? (1 point)
Y_Kistochka [10]

Answer: c

Explanation: because if it increases then it gets hotter

if it decreases then its getting colder.

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2 years ago
A candle is 49 cm in front of a convex spherical mirror that has a focal length
vitfil [10]

The convex spherical mirror is the diverging mirror. The image distance is 20.4 cm. The magnification is 0.417. The image is virtual and upright.

<h3>What is magnification?</h3>

Magnification is the ratio of image distance to the object distance.

Object distance is 49 cm and the focal length of convex mirror is 35 cm, then image distance is calculated by the lens maker formula.

1/f = 1/v +1/u

1/-35 = 1`/v +1/49

v= -20.4 cm

Thus, the image distance is 20.4 cm.

The magnification is given by

m = v/u

m = -20.4 / 49

m = 0.417

Thus, the magnification is 0.417.

The image formed is by virtual meeting of light rays and above the principle axis. Thus the image is virtual and upright.

Learn more about magnification.

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5 0
3 years ago
A straight wire that is 0.60 m long is carrying a current of 2.0 A. It is placed in a uniform magnetic field of strength 0.30 T.
Degger [83]

Answer:

The angle the wire make with respect to the magnetic field is 30°

Explanation:

It is given that,

Length of straight wire, L = 0.6 m

Current carrying by the wire, I = 2 A

Magnetic field, B = 0.3 T

Force experienced by the wire, F = 0.18 N

Let θ be the angle the wire make with respect to the magnetic field. Magnetic force is given by :

F=ILB\ sin\theta

\theta=sin^{-1}(\dfrac{F}{ILB})

\theta=sin^{-1}(\dfrac{0.18\ N}{2\ A\times 0.6\times 0.3\ T})

\theta=30^{\circ}

So, the angle the wire make with respect to the magnetic field is 30°. Hence, this is the required solution.

5 0
3 years ago
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