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Mumz [18]
3 years ago
8

Two men pushing a stalled car generate a net force of +690Nfor

Physics
1 answer:
Karolina [17]3 years ago
7 0

Answer:

The final momentum of the car is 4554 kg m/s.

Explanation:

Given that,

F = 690 N

Time = 6.6 sec

Momentum :

The momentum is the product of the force and change of time.

We need to calculate the final momentum

Using formula of momentum

\Delta p=F\times \Delta t

Where, F = force

t = time

Put the value into the formula

\Delta p=690\times6.6

\Delta p=4554\ kg-m/s

Hence, The final momentum of the car is 4554 kg m/s.

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A beam of protons is directed in a straight line along the +z direction through a region of space in which there are crossed ele
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Answer:

B = 7.6 T   direction of + x

Explanation:

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              F_{m} - F_{e} = 0

              F_{m} = F_{e}

              Fm = q E

             

The electric force is in the direction of the electric field because it is the charge of the positive proton, the electric force goes in the direction of –y, therefore, the magnetic force cancels this force must go in the direction of + y

 The magnetic force is

             F_{m} = q v x B = q v B sin θ

             θ = 90

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             B = 7.6 T

To find the direction of the magnetic field we use the right hand rule, the thumb goes in the direction of the proton velocity, the fingers extended in the direction of the magnetic field and the palm is the direction of force, for a positive charge.

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NASA is concerned about the ability of a future lunar outpost to store the supplies necessary to support the astronauts the supp
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Complete question :

NASA is concerned about the ability of a future lunar outpost to store the supplies necessary to support the astronauts the supply storage area of the lunar outpost where gravity is 1.63m/s/s can only support 1 x 10 over 5 N. What is the maximum WEIGHT of supplies, as measured on EARTH, NASA should plan on sending to the lunar outpost?

Answer:

601000 N

Explanation:

Given that :

Acceleration due to gravity at lunar outpost = 1.6m/s²

Supported Weight of supplies = 1 * 10^5 N

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Maximum weight of supplies as measured on EARTH :

Ratio of earth gravity to lunar post gravity:

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Hence, maximum weight of supplies as measured on EARTH should be :

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