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Mumz [18]
3 years ago
8

Two men pushing a stalled car generate a net force of +690Nfor

Physics
1 answer:
Karolina [17]3 years ago
7 0

Answer:

The final momentum of the car is 4554 kg m/s.

Explanation:

Given that,

F = 690 N

Time = 6.6 sec

Momentum :

The momentum is the product of the force and change of time.

We need to calculate the final momentum

Using formula of momentum

\Delta p=F\times \Delta t

Where, F = force

t = time

Put the value into the formula

\Delta p=690\times6.6

\Delta p=4554\ kg-m/s

Hence, The final momentum of the car is 4554 kg m/s.

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Newton’s second law states that the acceleration of an object is dependent on 1 variable which is the net force
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L'aigua es una mescla de d'oxigen i hidrogen
pshichka [43]

Answer:

Una Mezcla Homogénea es aquella mezcla en la que las sustancias que la forman poseen una combinación uniforme.Son ejemplos de Mezclas Homogéneas: Compuesta

Explanation:

Aire (es una mezcla de gases homogénea formada principalmente por de nitrógeno, oxígeno, vapor de agua, dióxido de carbono...)

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Mezcla de agua y sal disuelta

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3 years ago
In a car, 75 percent of the chemical energy of gasoline is lost as thermal
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3 0
3 years ago
it takes 90 j of work to stretch a spring 0.2 m from its equilibrium position. How muc work is needed to stretch it an additiona
Vinvika [58]

Work needed: 720 J

Explanation:

The work needed to stretch a spring is equal to the elastic potential energy stored in the spring when it is stretched, which is given by

E=\frac{1}{2}kx^2

where

k is the spring constant

x is the stretching of the spring from the equilibrium position

In this problem, we have

E = 90 J (work done to stretch the spring)

x = 0.2 m (stretching)

Therefore, the spring constant is

k=\frac{2E}{x^2}=\frac{2(90)}{(0.2)^2}=4500 N/m

Now we can find what is the work done to stretch the spring by an additional 0.4 m, that means to a total displacement of

x = 0.2 + 0.4 = 0.6 m

Substituting,

E'=\frac{1}{2}kx^2=\frac{1}{2}(4500)(0.6)^2=810 J

Therefore, the additional work needed is

\Delta E=E'-E=810-90=720 J

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

7 0
3 years ago
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