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Mumz [18]
3 years ago
8

Two men pushing a stalled car generate a net force of +690Nfor

Physics
1 answer:
Karolina [17]3 years ago
7 0

Answer:

The final momentum of the car is 4554 kg m/s.

Explanation:

Given that,

F = 690 N

Time = 6.6 sec

Momentum :

The momentum is the product of the force and change of time.

We need to calculate the final momentum

Using formula of momentum

\Delta p=F\times \Delta t

Where, F = force

t = time

Put the value into the formula

\Delta p=690\times6.6

\Delta p=4554\ kg-m/s

Hence, The final momentum of the car is 4554 kg m/s.

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Water drops fall from the edge of a roof at a steady rate. a fifth drop starts to fall just as the first drop hits the ground. a
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The height of the roof is <u>3.57m</u>

Let the drops fall at a rate of 1 drop per t seconds. The first drop takes 5t seconds to reach the ground. The second drop takes 4t seconds to reach the bottom of the 1.00 m window, while the 3rd drop takes 3t s to reach the top of the window.

Calculate the distances traveled by the second and the third drops s₂ and s₃, which start from rest from the roof of the building.

s_2=\frac{1}{2} g(4t)^2=8gt^2\\  s_3=\frac{1}{2} g(3t)^2=(4.5)gt^2

The length of the window s is given by,

s=s_2-s_3\\ (1.00 m)=8gt^2-4.5gt^2=3.5gt^2\\ t^2=\frac{1.00 m}{(3.5)(9.8m/s^2)} =0.02915s^2

The first drop is at the bottom and it takes 5t seconds to reach down.

The height of the roof h is the distance traveled by the first drop and is given by,

h=\frac{1}{2} g(5t)^2=\frac{25t^2}{2g} =\frac{25(0.02915s^2)}{2(9.8m/s^2)} =3.57 m

the height of the roof is 3.57 m



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