Answer:
F = 132N
Explanation:
Let the pulling force be F
Given the mass of the barrel is 12 Kg and The acceleration is 1.2 m/
We know that Net Force =
Now net force = F - mg
F - mg = ma
F = mg + ma
F = m(a+g) =
Note that there will be a downward force acting on the body which is equal to mg
Three units deformations observed in these bands.
<h3>What forces do a rubber band encounter?</h3>
Elastic force is the force that permits some materials to regain their former shape after being stretched or crushed. Thus, a stretched rubber band is subject to an elastic force.
The rubber band experiment uses a straightforward rubber band to show entropic force and a refrigeration cycle. The rubber band experiment involves stretching and then releasing a rubber band while measuring its temperature.
Always acting in the opposite direction of motion is friction. This indicates that if friction is there, it cancels out some of the force driving the motion (if the object is being accelerated). This results in a decreased acceleration and a smaller net force.
learn more about Elastic force refer
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By increasing or decreasing the height, we can do that....
Answer:
The rate of change of the height is - 4 ft/s
Solution:
As per the question:
Height of the person, y = 5 ft
The rate at which the person walks away,
Distance of the spotlight from the wall, x = 40 ft
Now,
To calculate the rate of change in the height, of the person when, x = 10 m:
From fig 1.
xy = 200 (1)
Differentiating the above eqn w.r.t time t:
Thus
(2)
From eqn (1):
When x = 10 ft
10y = 200
y = 20 ft
Using eqn (2):
so for the first one it will be longitudinal wave then the second is transverse wave and the third is electromagnetic wave