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enot [183]
3 years ago
9

Ferns that eject spores generally do so in pairs, with two spores flying off in opposite directions. The structure from which th

e spores are launched is quite lightweight. If it takes a certain amount of energy to eject each spore, explain how launching the spores in pairs provides for the greatest initial launch speed for each spore.
Physics
1 answer:
Furkat [3]3 years ago
5 0

Answer:

It cancels recoil.

Explanation:

For each action there is an equal an opposite reaction.

The principle of conservation of momentum tell us that if a single spore were ejected the fern would suffer a recoil from it. This recoil would take energy and speed from the spore. But if they are ejected in pairs the recoil is canceled and all the energy is transferred to the spores resulting in higher speeds.

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what is the kinetic energy of an object that has mass of 30 kilograms and move with a velocity of 20 m/s
kotegsom [21]
Kinetic Energy = 1/2 * m * v² 1/2 * 30 * 20² 1/2 * 30 * 400 12000/2 6000 J.
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3 years ago
Ubes have sides of equal lengths. What is the fastest way to measure the volume of a cube-shaped table?
Kryger [21]

The quickest technique to calculate the volume of a cube-shaped table is to use a ruler to measure one side, then multiply that figure by three. Option B is correct.

<h3 /><h3>How do you calculate the volume of a cube?</h3>

Assume the side length of the cube under consideration is L units. The volume of the cube is then equal to L³ cubic units.

The volume of a cube is;

V = L³

Ubes have equal-length sides. The quickest technique to calculate the volume of a cube-shaped table is to use a ruler to measure one side, then multiply that figure by three.

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A team of dogs accelerates a 290kg dogsled from 0 to 6.0m/s in 3.0 s. Assume that the acceleration is constant.Part AWhat is the
Mademuasel [1]

Answer:

(a) a=2m/sec^2

(b) 5220 j

(c) 1740 watt

(d) 3446.66 watt

Explanation:

We have given mass m = 290 kg

Initial velocity u = 0 m/sec

Final velocity v = 6 m/sec

Time t = 3 sec

From first equation of motion

v = u+at

So a=\frac{v-u}{t}=\frac{6-0}{3}=2m/sec^2

(a) We know that force is given by

F = ma

So force will be F=290\times 2=580N

(b) From second equation of motion we know that

s=ut+\frac{1}{2}at^2=0\times 3+\frac{1}{2}\times 2\times 3^2=9m

We know that work done is given by

W = F s = 580×9 =5220 j

(c) Time is given as t = 3 sec

We know that power is given as

P=\frac{W}{t}=\frac{5220}{3}=1740Watt

(d) Time t = 1.5 sec

So P=\frac{W}{t}=\frac{5220}{1.5}=3466.66Watt

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