Answer:
The time it took the bobsled to come to rest is 10 s.
Explanation:
Given;
initial velocity of the bobsled, u = 50 m/s
deceleration of the bobsled, a = - 5 m/s²
distance traveled, s = 250 m
Apply the following kinematic equation to determine the time of motion of the bobsled;
s = ut + ¹/₂at²
250 = 50t + ¹/₂(-5)t²
250 = 50t - ⁵/₂t²
500 = 100t - 5t²
100 = 20t -t²
t² - 20t + 100 = 0
t² -10t - 10t + 100 = 0
t (t - 10) - 10(t - 10) = 0
(t - 10)(t - 10) = 0
t = 10 s
Therefore, the time it took the bobsled to come to rest is 10 s.
Answer: 47.6 m/s
Explanation: Please see attached for the calculation and formula.
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Answer:
ρ = 1469 kg/m³
Explanation:
given,
mass of statue = 0.4 Kg
density of statue = 8 x 10³ kg/m³
tension in the string = 3.2 N
density of the fluid = ?
Volume of the statue

V = 5 x 10⁻⁵ m³
W = ρ g V
W = ρ x 9.8 x 5 x 10⁻⁵
now, tension on the string will be equal to
T = mg - W
3.2 = 0.4 x 9.8 - ρ x 9.8 x 5 x 10⁻⁵
ρ x 9.8 x 5 x 10⁻⁵ = 0.72
ρ = 1469 kg/m³
Answer:
0.055 * 5.1 = 0.2805
Explanation:
I used a calculator so it should be accurate! yw!! :D