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lilavasa [31]
3 years ago
14

Convert 35/ 8 to a decimal using long division. A) 0.2285714 B) 2.29 C) 4.225 D) 4.375

Mathematics
2 answers:
Georgia [21]3 years ago
7 0
D, you jist have to divide!
Ivanshal [37]3 years ago
5 0
The answer is d.)4.375
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Compare. Select &lt;, &gt;, or=.<br> 3.568 ? 3.577
alexira [117]

Answer:

3.568 < 3.577

Step-by-step explanation:

3.568 < 3.577

So 3.577 is greater than 3.568

5 0
3 years ago
Select the letter of the correct answer.
marishachu [46]

Answer:

C

Step-by-step explanation:

120 x 35% = should make 42

jus report if its not C

7 0
3 years ago
Read 2 more answers
If a number minus 3 is at most 12, or 1 more than 2 times the number is at least 25, then the number must be less than or equal
dezoksy [38]

Answer:

The statement is true.

Step-by-step explanation:

Let us assume that x is the required number.

Now, given that the number minus 3 is at most 12.

Hence, x - 3 ≤ 12

⇒ x ≤ 15 ......... (1)

And also given that 1 more than 2 times the number is at least 25.

Hence, 2x + 1 ≥ 25

⇒ 2x ≥ 24

⇒ x ≥ 12 .......... (2)

Therefore, from equations (1) and (2) we get the number must be greater than or equal to 12 or less than or equal to 15.

So, the statement is true. (Answer)

3 0
3 years ago
please explain how you got the answer please i need to see how you got that answer!! umm please someone give me it quick
koban [17]

Answer:

y>-2

Step-by-step explanation:

her mistake was she did -22-6= -28 but the correct solution is -22+6= -16

7 0
2 years ago
How to find the area under the standard normal curve between z 1.5 and z 2.5?
alisha [4.7K]
It is possible to calculate mathematically the area under the normal curve between any two values of z.
However, tables/software have been developed to give the areas under the normal curve to the left of particular values of z.  The function is the probability of Z<z, or P(Z<z).
The area between two values z1 and z2 (where z2>z1) is therefore 
P(Z<z2)-P(Z<z1).

For example, to find the area between  z1=1.5, z2=2.5
is 
P(Z<2.5)-P(Z<1.5)
=0.99379-0.93319
=0.06060

(above values obtained by software, such as R)
For example, the value P(Z<2.5) can be calculated using
P(Z<2.5)=erf(2.5/sqrt(2))/2+1/2
where erf(x) is a mathematical function that does not have an explicit formula (calculated by summation of series, or tabulated).
8 0
3 years ago
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