Answer:
a) The brake force = -535.7N
b) acceleration = - 1.2m/s^2
Explanation: Please find the attached files for the solution.
Answer:
Speed = 2.25 m/s
Explanation:
(Assume a running step is 1.5 m long)
Given the following data;
Energy = 0.6J
Power = 61 Watts
Mass = 68 kg
To find how fast the person running;
First of all, we would determine the total mechanical energy being dissipated by the person.
Total energy = 0.6 * 68
Total energy = 40.8 Joules
Next, we find the time;
Energy = power * time
40.8 = 61 * time
Time = 61/40.8
Time = 1.5 seconds
Finally, to find the speed;
Speed = distance/time
Speed = number of steps * time
Speed = 1.5 * 1.5
Speed = 2.25 m/s
The most useful meteorological measurement for forecasting freezing precipitation is b. radiosonde soundings
<h3>
Radiosonde </h3>
At high altitudes, radiosondes are battery-powered telemetry sensor bundles that detect altitude, pressure, temperature, relative humidity, wind (both speed and direction), and cosmic ray measurements. They are commonly taken into the atmosphere by weather balloons.
Rawindsonde is an acronym for radar wind sonde, a type of radiosonde that tracks its position as it rises through the sky to provide wind speed and direction. Another type of radiosonde is one that falls to the ground after being released from an aircraft, as opposed to being carried by weather balloons. The term "dropsondes" is used to describe this group of radiosondes. The majority of operational atmospheric data assimilation methods depend heavily on radiosondes.
Learn more about radiosonde here:
brainly.com/question/10510287
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- Height (h) = 10 m
- Density (ρ) = 1000 Kg/m^3
- Acceleration due to gravity (g) = 10 m/s^2
- We know, pressure in a fluid = hρg
- Therefore, the pressure exerted by a column of fresh water
- = hρg
- = (10 × 1000 × 10) Pa
- = 100000 Pa
<u>Answer</u><u>:</u>
<u>1000</u><u>0</u><u>0</u><u> </u><u>Pa</u>
Hope you could understand.
If you have any query, feel free to ask.
Answer:
The situation is not shown, however if one calculates torques about the pivot point, then the pivot point itself exerts no torque because the force applied by the pivot point exerts zero torque because Fp * L = 0 where L = 0 in this case.
If one wants to calculate torques about, say, the end of the ruler then one would need to calculate the torque applied by the pivot point.
