The answer is D using the work formula
W= F•d but if it was against gravity, it would be 0 if gravity is exerting the same amount, I would pick D using the formula, but I'm not so sure sorry
We know,
V= f× wavelength
10.5= f×0.15
f=10.5/0.15
f= 70 Hz
Explanation:
The formula to determine the eccentricity of an ellipse is the distance between foci divided by the length of the major axis
Answer:
T = 76.39°C
Explanation:
given,
coffee cup temperature = 95°C
Room temperature= 20°C
expression
![T( t ) = 20 + 75 e^{\dfrac{-t}{50}}](https://tex.z-dn.net/?f=T%28%20t%20%29%20%3D%2020%20%2B%2075%20e%5E%7B%5Cdfrac%7B-t%7D%7B50%7D%7D)
temperature at t = 0
![T( 0 ) = 20 + 75 e^{\dfrac{-0}{50}}](https://tex.z-dn.net/?f=T%28%200%20%29%20%3D%2020%20%2B%2075%20e%5E%7B%5Cdfrac%7B-0%7D%7B50%7D%7D)
T(0) = 95°C
temperature after half hour of cooling
![T( t ) = 20 + 75 e^{\dfrac{-t}{50}}](https://tex.z-dn.net/?f=T%28%20t%20%29%20%3D%2020%20%2B%2075%20e%5E%7B%5Cdfrac%7B-t%7D%7B50%7D%7D)
t = 30 minutes
![T( 30 ) = 20 + 75 e^{\dfrac{-30}{50}}](https://tex.z-dn.net/?f=T%28%2030%20%29%20%3D%2020%20%2B%2075%20e%5E%7B%5Cdfrac%7B-30%7D%7B50%7D%7D)
![T( 30 ) = 20 + 75 \times 0.5488](https://tex.z-dn.net/?f=T%28%2030%20%29%20%3D%2020%20%2B%2075%20%5Ctimes%200.5488)
T(30) = 61.16° C
average of first half hour will be equal to
![T = \dfrac{1}{30-0}\int_0^30(20 + 75 e^{\dfrac{-t}{50}})\ dt](https://tex.z-dn.net/?f=T%20%3D%20%5Cdfrac%7B1%7D%7B30-0%7D%5Cint_0%5E30%2820%20%2B%2075%20e%5E%7B%5Cdfrac%7B-t%7D%7B50%7D%7D%29%5C%20dt)
![T = \dfrac{1}{30}[(20t - \dfrac{75 e^{\dfrac{-t}{50}}}{\dfrac{1}{50}})]_0^30](https://tex.z-dn.net/?f=T%20%3D%20%5Cdfrac%7B1%7D%7B30%7D%5B%2820t%20-%20%5Cdfrac%7B75%20e%5E%7B%5Cdfrac%7B-t%7D%7B50%7D%7D%7D%7B%5Cdfrac%7B1%7D%7B50%7D%7D%29%5D_0%5E30)
![T = \dfrac{1}{30}[(20t - 3750e^{\dfrac{-t}{50}}]_0^30](https://tex.z-dn.net/?f=T%20%3D%20%5Cdfrac%7B1%7D%7B30%7D%5B%2820t%20-%203750e%5E%7B%5Cdfrac%7B-t%7D%7B50%7D%7D%5D_0%5E30)
![T = \dfrac{1}{30}[(20\times 30 - 3750 e^{\dfrac{-30}{50}} + 3750]](https://tex.z-dn.net/?f=T%20%3D%20%5Cdfrac%7B1%7D%7B30%7D%5B%2820%5Ctimes%2030%20-%203750%20e%5E%7B%5Cdfrac%7B-30%7D%7B50%7D%7D%20%2B%203750%5D)
![T = \dfrac{1}{30}[600 - 2058.04 + 3750]](https://tex.z-dn.net/?f=T%20%3D%20%5Cdfrac%7B1%7D%7B30%7D%5B600%20-%202058.04%20%2B%203750%5D)
T = 76.39°C
Momentum is conserved when carts are collided on a slanting plane.
To find the answer, we need to know about the conversation of momentum.
<h3>What's the conversation of momentum?</h3>
- Conservation of linear momentum says the total momentum before the collision and after the collision remains the same.
- Mathematically, m1u1+m2u2 = m1v1+m2v2
<h3>How is the momentum conserved when collision occurs on a slanting plane?</h3>
- On a slanting plane, the velocity has two components,
- horizontal component
- horizontal component Vertical component
- So, its momentum has also similar two components.
- The momentum is conserved along horizontal direction and vertical direction separately.
Thus, we can conclude that the momentum is conserved when carts are collided on a slanting plane.
Learn more about the conversation of momentum here:
brainly.com/question/7538238
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