It's kinda tough, since we don't know the actual numerical locations of the points, only an approximate picture.
The big ball has 11 times the mass of the small ball, so the small ball is 11 times as far from the barycenter as the big ball is.
If any of the points is marked at the actual barycenter, it can only be point-A .
Answer:
Acceleration, a = 0.5m/s²
Explanation:
Given the following data;
Force, f = 20N
Mass = 40kg
To find the acceleration;
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
Where;
F represents force.
m represents the mass of an object.
a represents acceleration.
Making acceleration (a) the subject, we have;
Substituting into the equation;

Acceleration, a = 0.5m/s²
Therefore, the acceleration of the bookcase is 0.5m/s²
Answer:
stone with lesser mass can not go far because of firm structure but football that has greatet mass can go farther because of the structure that makes it move further when a force was applied to it
Answer:
B. After a photon of light is absorbed by certain metals, electrons are found to be ejected from the metals. This is because the energy contained in the massless photon is used to eject an electron with mass out of the metal.
Explanation:
Before, in the early days, it was proposed to form a combined theory by joining the theory of conservation of mass and the theory of conservation of energy and form a combined theory of conservation of mass-energy. It was done to explain a particular theory of
.
The
is the emission of the electrons form the surface of a metal when light energy strikes on it. Here, in this phenomenon, both mass and energy is conserved.
When the light strikes a metal surface, electrons gets ejected from the surface. The energy of the photon is used to eject the electron form the metal surface.
Responder: A.) 24.5m / s B.) 30.625m C.) 89.375m
Explicación:
Dado lo siguiente:
Altura desde la cual se cae el cuerpo = 120 m
Tiempo (t) = 2.5s
A.) La velocidad que toma:
El cuerpo cayó desde una altura;
velocidad inicial (u) = 0
Para calcular v:
V = u + en
Donde a = aceleración debido a la gravedad = 9.8m / s
v = 0 + (9.8) (2.5)
v = 24.5 m / s
B) Cuánto ha disminuido.
Usando la ecuación de movimiento:
S = ut + 0.5at ^ 2
Donde S = distancia
S = 0 × 2.5 + 0.5 (9.8) (2.5 ^ 2)
S = 0 + 0.5 (9.8) (6.25)
S = 30.625 m
Esta es la distancia recorrida después de 2.5 segundos Altura o distancia ha disminuido en 30.625 m
C.) ¿CUÁNTO FALTA? Por lo tanto, 120m - 30.625m = 89.375m