A chemical property is a change in classification in matter I think
Answer:
T = 273 + (-50) = 273 – 50 = 223 K
R = 188.82 J / kg K for CO2
Density (Martian Atmosphere) = P / RT = 900 / 188.92 x 223 = 900 / 42129.16 = 0.0213 kg / 
T = 273 +18 = 291 K, R = 287 J / kg k (for air) P = 101.6 k Pa = 101600 Pa
Density (Earth Atmosphere) = P / RT = 101600 / 287 x 291 = 1.216 kg /
Answer:
The induced emf 1.43 s after the circuit is closed is 4.19 V
Explanation:
The current equation in LR circuit is :
.....(1)
Here I is current, V is source voltage, R is resistance, L is inductance and t is time.
The induced emf is determine by the equation :
Differentiating equation (1) with respect to time and put in above equation.
Substitute 6.05 volts for V, 0.655 Ω for R, 2.55 H for L and 1.43 s for t in the above equation.
1. Communication
In early ages people were using letters to communicate between them. Now days instantly we can call one person from anywhere, these are based on optical fiber communication and it is an application of physics.
2. Transportation
We can travel from place to anther place by aeroplane , these technologies are introduced after advancement in physics.
3. Construction
Earlier people used to stay in small houses, now days apartments with many number of storeys are built by considering all the forces coming on the structure.
4. Medical Department
The invention of many equipment increased the health of humans.
5. Weather forecasting
The prediction of weather considering all the available factors, prediction of natural disasters all are application of physics.
Answer:
(a) Number of electrons per second strike the target is 3.125 x 10¹⁵.
(b) Charge that strikes the target in 0.750 s is 3.75 x 10⁻⁴ C .
Explanation:
(a) Let n be the number of electrons per second strike the target. We know that current (I) is given by the relation :
I = n x e
Here e is charge of electron.
Substitute 0.500 x 10⁻³ A for I and 1.6 x 10⁻¹⁹ C for e in the above equation.
0.500 x 10⁻³ = n x 1.6 x 10⁻¹⁹
n = 3.125 x 10¹⁵
(b) Let q be the charge that strikes the target. We know that :
q = I x t
Here I is current and t is time.
Substitute 0.500 x 10⁻³ A for I and 0.750 s for t in the above equation,
q = 0.500 x 10⁻³ x 0.750
q = 3.75 x 10⁻⁴ C
