The diagram below represents a bicyclist at the top of a hill, with four points labeled W, X, Y, and Z. Assume that
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Answer:
If a pitch vibrates at 880 cycles, the octave below would vibrate at 440 cycles.
Explanation:
Pitch of sound is defined as relative highest and the lowest point of sound. The pitch is dependent on frequency of vibration.
Octave is defined as a tone which is formed due to merging of two different tone. The resultant tone is merged so well that it sound like a single tone.
Thus, Number cycle in octave =
Number cycle in octave =
Number cycle in octave = 440
Thus, If a pitch vibrates at 880 cycles, the octave below would vibrate at 440 cycles.
(a) 3.5 Hz
The angular frequency in a spring-mass system is given by
where
k is the spring constant
m is the mass
Here in this problem we have
k = 160 N/m
m = 0.340 kg
So the angular frequency is
And the frequency of the motion instead is given by:
(b) 0.021 m
The block is oscillating up and down together with the upper end of the spring. The block will lose contact with the spring when the direction of motion of the spring changes: this occurs when the spring is at maximum displacement, so at
x = A
where A is the amplitude of the motion.
The maximum displacement is given by Hook's law:
where
F is the force applied initially to the spring, so it is equal to the weight of the block:
k = 160 N/m is the spring constant
Solving for A, we find