Answer:
It would take the object 5.4 s to reach the ground.
Explanation:
Hi there!
The equation of the height of a free-falling object at any given time, neglecting air resistance, is the following:
h = h0 + v0 · t + 1/2 · g · t²
Where:
h = height of the object at time t.
h0 = initial height.
v0 = initial velocity.
g = acceleration due to gravity (-32.2 ft/s² considering the upward direction as positive).
t = time
Let´s supose that the object is dropped and not thrown so that v0 = 0. Then:
h = h0 + 1/2 · g · t²
We have to find the time at which h = 0:
0 = 470 ft - 1/2 · 32.2 ft/s² · t²
Solving for t:
-470 ft = -16.1 ft/s² · t²
-470 ft / -16.1 ft/s² = t²
t = 5.4 s
True if you have proper stance and use your body the right way then the ball will be below your waist to allow for more control.
Answer:
Explanation:
Given:
Let mass of the particle B be, 
then the mass of particle A, 
Energy stored in the compressed spring, 
Now when the compression of the particles with the spring is released, the spring potential energy must get converted into the kinetic energy of the particles and their momentum must be conserved.
Kinetic energy:
.............................(1)
<u>Using the conservation of linear momentum:</u>
.............................(2)
Put the value of 
from eq. (2) into eq. (1)
...........................(3)
<u>Now the kinetic energy of particle B:</u>
Put the value of 
form eq. (3) into eq. (1):
<u>Now the kinetic energy of particle A:</u>
<u />
<u />
<u />
<u />
The real answer would be 16.5 but since you want to have a full number it would be 16
