The distance between two particles that are <em>in phase</em>
Answer:
Increases
Explanation:
The expression for the capacitance is as follows as;

Here, C is the capacitance,
is the permittivity of free space, A is the area and d is the distance between the parallel plate capacitor.
It can be concluded from the above expression, the capacitance is inversely proportional to the distance. According to the given problem, the capacitor is disconnected from the battery and the distance between the plates is increased. Then, the capacitance of the given capacitor will decrease in this case.
The expression for the energy stored in the parallel plate capacitor is as follows;

Here, E is the energy stored in the capacitor, C is the capacitance and Q is the charge.
Energy stored in the given capacitor is inversely proportional to the capacitor. The charge on the capacitor is constant. In the given problem, as the distance between the parallel plates is being separated, the energy stored in this capacitor increases.
Therefore, the option (c) is correct.
Answer:
10m/s
Explanation:
Using the law of conservation of momentums
M1u1+m2u2 = (m1+m2)v
Substitute.
4000(10)+1500(10) = (4000+1500)v
40,000+15,000 = 5,500v
55000 = 5500v
v = 55000/5500
v= 10m/s
Hence the velocity of the truck after Collision is 10m/s
Answer:
A, C, D
Explanation:
Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.
and according to Newton's 4th law: An object that is at rest will stay at rest unless a force acts upon it. An object that is in motion will not change its velocity unless a force acts upon it.