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Mumz [18]
3 years ago
10

A student is given a red and a blue liquid. The two samples of liquids are heated in identical beakers over identical Bunsen bur

ners. The red liquid shows a dramatically faster increase in temperature. Which of these is the most likely explanation for this?
Physics
2 answers:
Savatey [412]3 years ago
4 0
The red beaker has a smaller specific heat
Morgarella [4.7K]3 years ago
4 0

Explanation :

It is given that a student is given a red and a blue liquid. The two samples of liquids are heated in identical beakers over identical Bunsen burners.

It is observed that the red liquid shows a dramatically faster increase in temperature.

This observation can be explained in terms of specific heat. It is defined as the heat required to raise the temperature.

We know that the specific heat of any liquid is given by :

c=\dfrac{Q}{m\Delta T}

Where c is the specific heat.

m is the mass of the substance.

Q is the amount of heat.

\Delta T is the change in temperature.

So, it is clear that the specific heat capacity is inversely proportional to the temperature.

The better explanation for this can be the specific heat of the red liquid is less because it drastically increases in temperature.

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Answer:

D). Field lines circle the Earth from east to west.  

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Name all the elements are in a molecule of indigo
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Two objects 5 kg and 7 kg are attached to the end of inextensible string which passes over frictionless pulley
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Answer:

ans:

tenson(T) = 20 N

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An apple dropped from the branch of a tree hits the ground in 0.5 s. If the acceleration of the apple during its motion is 10 ms
Ipatiy [6.2K]

Given that,

Time = 0.5 s

Acceleration = 10 m/s²

(I). We need to calculate the speed of apple

Using equation of motion

v=u+at

Where, v = speed

u = initial speed

a = acceleration

t = time

Put the value into the formula

v=0+10\times0.5

v=5\ m/s

(III). We need to calculate the height of the branch of the tree from the ground

Using equation of motion

s=ut+\dfrac{1}{2}gt^2

Put the value into the formula

s=0+\dfrac{1}{2}\times10\times(0.5)^2

s=1.25\ m

(II). We need to calculate the average velocity during 0.5 sec

Using formula of average velocity

v_{avg}=\dfrac{\Delta x}{\Delta t}

v_{avg}=\dfrac{x_{f}-x_{i}}{t_{f}-t_{0}}

Where, x_{f}= final position

x_{i} = initial position

Put the value into the formula

v_{avg}=\dfrac{1.25+0}{0.5}

v_{avg}=2.5\ m/s

Hence, (I). The speed of apple is 5 m/s.

(II). The average velocity during 0.5 sec is 2.5 m/s

(III). The height of the branch of the tree from the ground is 1.25 m.

7 0
3 years ago
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