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Mumz [18]
3 years ago
10

A student is given a red and a blue liquid. The two samples of liquids are heated in identical beakers over identical Bunsen bur

ners. The red liquid shows a dramatically faster increase in temperature. Which of these is the most likely explanation for this?
Physics
2 answers:
Savatey [412]3 years ago
4 0
The red beaker has a smaller specific heat
Morgarella [4.7K]3 years ago
4 0

Explanation :

It is given that a student is given a red and a blue liquid. The two samples of liquids are heated in identical beakers over identical Bunsen burners.

It is observed that the red liquid shows a dramatically faster increase in temperature.

This observation can be explained in terms of specific heat. It is defined as the heat required to raise the temperature.

We know that the specific heat of any liquid is given by :

c=\dfrac{Q}{m\Delta T}

Where c is the specific heat.

m is the mass of the substance.

Q is the amount of heat.

\Delta T is the change in temperature.

So, it is clear that the specific heat capacity is inversely proportional to the temperature.

The better explanation for this can be the specific heat of the red liquid is less because it drastically increases in temperature.

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Answer: 7,000 ohms

Explanation:

From the equation of ohms law V= IR

V=21 volt

I = 3 MA = 3.0×10^-3 A

So by evaluating, we have.

V= IR

21= 3.0×10^-3 × R

Then R = 21/3.0×10^-3

R= 7,000 ohms//.

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12. What is the net force on a 1-kg apple held at rest in your hand?
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What purpose does a female pine cone serve?
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5 0
3 years ago
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Which of the following devices is associated with the reception of radio signals?
ki77a [65]
What are the "following" devices ? ?
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3 years ago
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Monochromatic light of wavelength 385 nm is incident on a narrow slit. On a screen 3.00 m away, the distance between the second
LiRa [457]

To solve this problem it is necessary to apply the concepts related to the concept of overlap and constructive interference.

For this purpose we have that the constructive interference in waves can be expressed under the function

a sin\theta = m\lambda

Where

a = Width of the slit

d = Distance of slit to screen

m = Number of order which represent the number of repetition of the spectrum

\theta = Angle between incident rays and scatter planes

At the same time the distance on the screen from the central point, would be

sin\theta = \frac{y}{d}

Where y = Represents the distance on the screen from the central point

PART A ) From the previous equation if we arrange to find the angle we have that

\theta = sin^{-1}(\frac{y}{d})

\theta = sin^{-1}(\frac{1.4*10^{-2}}{3})

\theta = 0.2673\°

PART B) Equation both equations we have

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a \frac{y}{d} = m\lambda

Re-arrange to find a,

a = \frac{(2)(385*10^{-9})(3)}{(1.4*10^{-2})}

a = 1.65*10^{-4}m

8 0
3 years ago
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