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Mumz [18]
4 years ago
10

A student is given a red and a blue liquid. The two samples of liquids are heated in identical beakers over identical Bunsen bur

ners. The red liquid shows a dramatically faster increase in temperature. Which of these is the most likely explanation for this?
Physics
2 answers:
Savatey [412]4 years ago
4 0
The red beaker has a smaller specific heat
Morgarella [4.7K]4 years ago
4 0

Explanation :

It is given that a student is given a red and a blue liquid. The two samples of liquids are heated in identical beakers over identical Bunsen burners.

It is observed that the red liquid shows a dramatically faster increase in temperature.

This observation can be explained in terms of specific heat. It is defined as the heat required to raise the temperature.

We know that the specific heat of any liquid is given by :

c=\dfrac{Q}{m\Delta T}

Where c is the specific heat.

m is the mass of the substance.

Q is the amount of heat.

\Delta T is the change in temperature.

So, it is clear that the specific heat capacity is inversely proportional to the temperature.

The better explanation for this can be the specific heat of the red liquid is less because it drastically increases in temperature.

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Find the distance traveled in one back-and-forth swing by the weight of a 12 in. Pendulum that swings through a 75 degree angle.
tia_tia [17]

The distance traveled by pendulum, in one back-and-forth swing is 75.75 inches.

The period of pendulum can be calculated by

T = 2\pi \sqrt {\dfrac Lg}

Where,

T - period

L - length = 12 inches

g- gravitational acceleration  = \bold {9.8\rm \ m/s^2}

Put the values,

T = 2\pi \sqrt {\dfrac {12}{9.8}}\\\\T = 2 \times 3.14 \times \sqrt {0.122}\\\\T = 2.191

Now, the angular displacement of the pendulum can be calculated by,

\theta = A\times\rm \  cos(\omega T)

Where,

A- amplitude

\theta - angle  = 75^o

\omega - angular displacement = 2\pi/T = 2.866 m

Put the values and calculate for \omega,

75 = A\times{\rm \  cos}(2.866\times 2.191)\\\\75 =A \times cos\ 6.26\\\\A =\dfrac {75}{0.99}\\\\A = 75.75 \rm \ inches

Therefore, the distance traveled by pendulum, in one back-and-forth swing is 75.75 inches.

To know more about Amplitude of pendulum,

brainly.com/question/14840171

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