Answer:
230.4 s
Explanation:
The speed of car A is

and the distance travelled is

so the time taken for car A is

The speed of car B is

and the distance travelled is

so the time taken for car B is

So the difference in time is

Which corresponds to

so car B arrived 230.4 s before car A.
Answer:
i) 0.7
ii) 1.39
iii) 0.6
Next time, when compiling a Physics question, ensure you put the unit of each measurement.
Explanation:
i) T = time of flight = 
where u = speed = 4, A = 60 and g = acceleration due to gravity = 10 (It is a constant);
Subsituting the values, we have: T =
= 0.7
ii) distance travel = Range = R = 
where u = speed = 4, A = 60 and g = acceleration due to gravity = 10 (It is a constant);
Subsituting values, we have: R =
= 1.39
iii) Maximum Height = H = 
where u = speed = 4, A = 60 and g = acceleration due to gravity = 10 (It is a constant);
Subsituting values, we have:
= 0.6
C) In the absence of an unbalanced force, an object at rest will stay at rest and an object in motion will stay in motion.
hope this helps and have a great day :)
Answer:
10kg
Explanation:
Let PE=potential energy
PE=196J
g(gravitational force)=9.8m/s^2
h(change in height)=2m
m=?
PE=m*g*(change in h)
196=m*9.8*2
m=10kg