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3 years ago

Explain how balanced and unbalanced forces effect an objects motion differently

1 answer:

5 0

Balanced Forces acting on an object will not change the object's motion. Unbalanced Forces acting on an object will change the change the object's motion.

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A person jogs 4.o km in 32 minutes then 2.0 km in 22 minutes and finally 1.0 km in 16 minutes. What is the joggers average speed

AlladinOne [14]

Average speed = distance travelled / time used

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3 years ago

Select the correct answer.

Alexeev081 [22]

For the scale od the paraboliczne curviczne Ur

3 0

3 years ago

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The last page of a book is numbered 764. The book is 3.0 cm thick, not including its covers. What is the average thickness (in c

Inessa [10]

Answer:

Thickness of each page will be 0.00785 cm

So option (E) will be correct answer

Explanation:

We have given that last page on the book is numbered as 764

So total number of pages in the book $=\frac{764}{2}=382pages$ ( as each page is numbered in both side )

Total thickness of the book = 3 cm

We have to found the thickness of the each page

So thickness of each page will be $=\frac{3}{382}=0.00785cm$

So option (E) is correct option

7 0

3 years ago

a charge of 7.2x10^-5C is placed in an Electric field with a strength of 4.8x10^5N/C. if the Electric potential energy of the ch

Alecsey [184]

Answer:

$d= 2.2 m$

Explanation:

The data given in the question is

Charge : q = $7.2 \times 10^{-5} C$

Electric field Strength : E = $4.8 \times 10^{5} N/C$

Electrical potential Energy : U = $75J$

Let, the distance be "d"

So, the formula for Electrical potential energy is

$U= q \times E \times d$

Simplified formula for distance become

$d=\frac{U}{q \times E}$

Now , insert the value

$d=\frac{75 J}{7.2 \times 10^{-5}C \times 4.8 \times 10^5 N/C}$

or,

$d=2.17 m$

Rounding off

$d= 2.2 m$

3 0

3 years ago

Mercury is added to a cylindrical container to a depth d and then the rest of the cylinder is filled with water.

VARVARA [1.3K]

Answer:

0.05m

Explanation:

Density of water = ρ(w) = 1000 kg/ m³ ;

Density of Mercury = ρ(m) = 13628.95 kg/ m³

Total pressure at bottom of cylinder=1.1atm

Therefore, pressure due to water and mercury =1.1-1 =atm

0.1atm=10130pa

The pressure at the bottom is given by,

ρ(w) x g[0.4 - d] + ρ(m) x g x d = 10130

1000 x 9.8[0.4 - d] + 13628.95 x 9.8 d = 10130

3924 - 9810d + 133416d= 10130

123606d= 6206

d= 6202/123606

d= 0.05m

Depth of mercury alone = d = 0.05m

8 0

3 years ago

Read 2 more answers