Question

Determine the acceleration that result when a 12-N net force is applied to a 3-kg object and then to a 6-kg object

Answer 1

For 3 kg mass: F = $\lpha ma,a$ = $\frac{F}{m}$ = $\frac{12N}{3kg}$ = 4$\lpha m$ / $s^{2}$

For 6 kg mass: F = $\lpha ma,a$ = $\frac{F}{m}$ = $\frac{12N}{6kg}$ = 2$\lpha m$ / $s^{2}$

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