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BaLLatris [955]
3 years ago
10

All members of group 8 have similair reactivity because

Chemistry
1 answer:
vova2212 [387]3 years ago
6 0

All members of group 8 have similar reactivity because they all have  the  same number of valence electrons and similar chemical properties.

Hope that  this helps, have a wonderful day, chao!!

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Number of electrons the atom my accept from another atom?
ZanzabumX [31]

Answer:

Yes atoms can accept the electrons from another atom like

Chlorine accept electron from hydrogen.

Explanation:

8 0
3 years ago
How does removing thermal energy from liquid water affect the molecules in the water?
galina1969 [7]

Answer:

For deposition to happen, thermal energy must be removed from the gas. ... As water vapor loses thermal energy, it changes into solid frost. States of Water. Water is the only substance that exists naturally as a solid, a liquid, and a gas within Earth's temperature range.

Explanation:

3 0
3 years ago
A bottle containing 415 g of cleaning solution is used to clean hospital equipment. If the cleaning solution has a specific grav
neonofarm [45]

Answer: 483 mL of the cleaning solution are used to clean hospital equipment

Explanation:

The question requires us to calculate the volume, in mL, of solution is used to clean hospital equipment, given that 415g of this solution are used and the specific gravity of the solution is 0.860.

Measurements > Density

Specific gravity is defined as the ratio between the density of a given substance to the density of a reference material, such as water:

Specific\text{ gravity = }\frac{density\text{ of substance}}{density\text{ of reference substance}}

The density of a substance is defined as the ratio between the mass and the volume of this substance:

density=\frac{mass}{volume}

Considering the reference substance as water and its density as 1.00 g/mL, we can determine the density of the substance which specific gravity is 0.860:

0.860=\frac{density\text{ of substance}}{1.00g/mL}\rightarrow density\text{ of substance = 0.860g/mL}

Thus, taking water as the reference substance, we can say that the density of the cleaning solution is 0.860 g/mL.

Now that we know the density of the cleaning solution (0.860 g/mL) and the mass of solution that is used to clean hospital equipment (415g), we can calculate the volume of solution that is used to clean the equipment:

\begin{gathered} density=\frac{mass}{volume}\rightarrow volume=\frac{mass}{density} \\  \\ volume=\frac{415g}{0.860g/mL}=483mL \end{gathered}

Therefore, 483 mL of the cleaning solution are used to clean hospital equipment.

6 0
1 year ago
How many grams of KCN are in 10.0 ml of a 0.10 M solution?
attashe74 [19]

Explanation:

As it is known that molarity is the number of moles present in a liter of solution.

Mathematically,       Molarity = \frac{no. of moles}{Volume in liter}

As it is given that molarity is 0.10 M and volume is 10.0 ml. As 1 ml equals 0.001 L. Therefore, 10.0 ml will also be equal to 0.01 L.

Hence, putting these values into the above formula as follows.

                  Molarity = \frac{no. of moles}{Volume in liter}

                  0.10 M = \frac{no. of moles}{0.01 L}

                        no. of moles = 0.001 mol

As molar mass of KCN is equal to 65.12 g/mol. Therefore, calculate the mass of KCN as follows.

                 No. of moles = \frac{mass}{molar mass}

                                 0.001 mol = \frac{mass}{65.12 g/mol}

                                 mass = 0.06152 g

Thus, we can conclude that 0.06152 grams of KCN are in 10.0 ml of a 0.10 M solution.

3 0
3 years ago
Purification of chromium can be achieved by electrorefining chromium from an impure chromium anode onto a pure chromium cathode
mylen [45]

Answer:

696 h

Explanation:

Let's consider the reduction of Cr³⁺.

Cr³⁺(aq) + 3e⁻ → Cr(s)

We can establish the following relations.

  • The molar mass of Cr is 52.0 g/mol.
  • 1 mol of Cr is deposited when 3 moles of e⁻ circulate.
  • 1 mole of e⁻ has a charge of 96468 c (Faraday's constant).
  • 1 A = 1 c/s
  • 1 h = 3600 s

<em>How many hours will it take to plate 13.5 kg of chromium onto the cathode if the current passed through the cell is held constant at 30.0 A?</em>

13.5 \times 10^{3} gCr.\frac{1molCr}{52.0gCr} .\frac{3mol/e^{-} }{1molCr} .\frac{96468c}{1mol/e^{-}} .\frac{1s}{30.0c} .\frac{1h}{3600s} =696 h

3 0
3 years ago
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