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pickupchik [31]
3 years ago
10

Both suspensions and colloids are heterogeneous mixtures. Define and characterize a suspension, listing similarities and differe

nces to a colloid. Give several examples of suspensions.
Chemistry
1 answer:
loris [4]3 years ago
4 0
Suspension mixture that separates into individual components with time. ​<span>Examples of suspended solutions include salt water, sand in water, and muddy water.</span>
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What is the vapor pressure of a solution that contains 70.0 mL of ether and 30.0 mL of benzene?
Lera25 [3.4K]

Answer:

it is 50

if I m right pls mark me brainliest

6 0
3 years ago
In the laboratory, a quantity of I2 was reacted with excess H2 to give 1.26 moles of HI. It is also known that the percent yield
Anon25 [30]

Answer:

1.008moles of iodine

Explanation:

Hello,

This question requires us to calculate the theoretical yield of I₂ or number of moles that reacted.

Percent yield = (actual yield / estimated yield) × 100

Actual yield = 1.2moles

Estimated yield = ?

Percentage yield = 84%

84 / 100 = 1.2 / x

Cross multiply and solve for x

100x = 84 × 1.2

100x = 100.8

x = 100.8/100

x = 1.008moles

1.008 moles of I₂ reacted in excess of H₂ to give 1.2 moles of HI

5 0
4 years ago
What is the instantaneous rate of formation of product C given the following information: a. Stoichiometric equation A+ B2C+ D b
quester [9]

Answer:

1.728 mol /(L*min)

Explanation:

Hello,

In the attached photo, you'll find the numerical procedure for your question.

- Take into account that the negative sign is eligible for reagents and positive for products.

Best regards!

6 0
3 years ago
How many formula units are in 9.8 grams of calcium hydroxide?
Neporo4naja [7]

Answer:

There are 9.8 ×1021. formula units in 10,005.8gCaO 

5 0
3 years ago
How much work (in J) is involved in a chemical reaction if the volume decreases from 4.35 to 1.20 L against a constant pressure
Marianna [84]

Answer:

W = -262 J.

Explanation:

Hello there!

In this case, according to the given information, we can recall the definition of work in terms of constant pressure and variable volume as follows:

W=P(V_2-V_1)

So we plug in the given pressure and volumes to obtain:

W=0.822atm(1.20L-4.35L)\\\\W=-2.60atm*L

Now, we convert this number to J (Pa*m³) by using the shown below conversion factor:

W=-2.60atm*L*\frac{101325Pa}{1atm} *\frac{1m^3}{1000L}\\\\W=-262J

Regards!

3 0
3 years ago
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