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tiny-mole [99]
4 years ago
14

In Earth's water cycle, evaporation takes place as solid ice and snow are converted to water vapor. true or false?

Chemistry
2 answers:
Vanyuwa [196]4 years ago
8 0

Answer:

True, evaporation takes place as solid ice and snow are converted to water vapor discussed below.

Explanation:

  • The water cycle procedure shows how the water vaporize from the surface of the Earth, get up into the atmosphere cool down and condenses into snow and rain in clouds and falls back to earth as precipitation.
  • Evaporation is the procedure in which water changes into vapor form from its liquid form.
  • When it was in water vapor form it moves in the atmosphere.
  • The 80% of water which delivered in the form of precipitation such as rain, snow, hail or steel, evaporates from the ocean surface.

valentinak56 [21]4 years ago
4 0
This is true, vapor is just evaporated water. Like in machines, you have to fill it up with water so your machine can produce the water vapor. Hope this helps!!
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Sometimes people do not want to change their belief regardless of the evidence.
bagirrra123 [75]

Answer:

True

Explanation:

Ex. People against vaccines tend to believe crazy theories over facts because they think they'll end up brainwashing them.

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3 years ago
Does the atomic mass of an atom change when an electron is added or removed?
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3 years ago
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The fertilizer ammonium sulfate, (NH4)2SO4, is prepared by the reaction between ammonia (NH3) and sulfuric acid:
kumpel [21]

The mass of ammonia required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄ is 6.18 * 10⁴ Kg of ammonia.

<h3>What mass in kilograms of ammonia are required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄?</h3>

The mass of ammonia required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄ is determined from the mole ratio of the reaction.

The mole ratio of the reaction is obtained from the balanced equation of the reaction given below:

  • 2NH₃(g) + H₂SO₄(aq) → (NH₄)₂SO₄(aq)

Mole ratio of NH₃ and (NH₄)₂SO₄ is 2: 1

Mass of 2 moles of ammonia = 2 * 17 = 34 g

Mass of 1 mole of (NH₄)₂SO₄ = 132 g

Mass of ammonia required = 34/132 *  2.40 × 10⁵ kg

Mass of ammonia required = 6.18 * 10⁴ Kg of ammonia.

In conclusion, the mole ratio is used to determine the mass of ammonia required.

Learn more about mole ratio at: brainly.com/question/19099163

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4 0
2 years ago
Name the following bases<br> -Ba(OH)2<br> - Ca(OH)2<br> -RbOH
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3 0
3 years ago
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Calculate the concentration of the resulting sodium oxalate solution if 0.1005 g of Na2C2O4 was used.
sashaice [31]

Answer:

0.00500M of Na₂C₂O₄

Explanation:

<em>When are dissolved in 150 mL of 1.0 M H2SO4.</em>

<em />

We can solve this problem finding molarity of sodium oxalate: That is, moles of Na2C2O4 per liter of solution. Thus, we need to convert the 0.1005g to moles using molar mass of sodium oxalate (134g/mol) and dividing in the 0.150L of the solution:

0.1005g * (1mol / 134g) = 7.5x10⁻⁴ moles of Na₂C₂O₄

In 0.150L:

7.5x10⁻⁴ moles of Na₂C₂O₄ / 0.150L =

<h3>0.00500M of Na₂C₂O₄</h3>
4 0
3 years ago
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