A. H2O is the substance reduced.
H2O + 2e^(-) →H_2 + 2OH^(-)
The substance that gains electrons is reduced.
Remember OIL <em>RIG </em>(<em>R</em>eduction <em>I</em>s <em>G</em>ain of electrons) and
LEO the lion says <em>GER</em> (<em>G</em>ain of <em>E</em>lectrons is <em>R</em>eduction).
1.) MgO + Fe --> FeO + Mg
2.) H + I --> HI
3.) Na + I --> NaI
4.) NaO + H2O --> NaOH + H
The balanced chemical reaction:
<span>5C + 2SO2 → CS2 + 4CO
</span>
We are given the amount of coke to be used for the reaction. This will be the starting point for the calculations.
8 mol C ( 1 mol CS2 / 5 mol C ) = 1.6 mol CS2
