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rusak2 [61]
3 years ago
5

Wave speed?_____ Frequency?_____ Wavelength?_____

Physics
1 answer:
Andru [333]3 years ago
3 0

Answer:

wave speed 200 m/s

wavelength 2 m

frequency = 100 Hz

Explanation:

there are 3 waves

v = 200m/s

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A boom box, stereo set.
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Three collinear forces,F1=45N west,F2=63N east and an unknown force F3 are applied to an object.The resultant force of the three
Greeley [361]

Take east to be the positive direction. Then the resultant force from adding <em>F</em>₁ and <em>F</em>₂ is

<em>F</em>₁ + <em>F</em>₂ = (-45 N) + 63 N = 18 N

which is positive, so it's directed east.

To this we add a third force <em>F</em>₃ such that the resultant is 12 N pointing west, making it negative, so that

18 N + <em>F</em>₃ = -12 N

<em>F</em>₃ = -30 N

So <em>F</em>₃ has a magnitude of 30 N and points west.

6 0
3 years ago
As shown above an adhesive has been applied to contacting faces of two blocks so that the blocks interact with an adhesive force
rusak2 [61]

The magnitude of the adhesive force allows the top block to remain

attached to the bottom when the blocks and the wire are balanced.

The option that must be true is; \mathbf{W_{bottom} = F_{adhesion}}

Reason:

The tension exerted by the wire attached to the top block = T

Magnitude of the adhesive = F_{adhesion}

Weight of the top block = W_{top}

Weight of the bottom block = W_{bottom}

Given that with the exertion of the tension, the two blocks remain at rest, we have;

  • T =  W_{top} + W_{bottom}

The adhesive causes the bottom block to remain attached to the top block, we have;

Therefore, the magnitude of the adhesive force adds the bottom weight, to the top, weight, which gives;

The magnitude of the adhesive force = The weight of the bottom block

Therefore;

  • W_{bottom} = F_{adhesion}

Learn more here:

brainly.com/question/18907970

8 0
3 years ago
Which of the following is not the result of nuclear decay.
svlad2 [7]

Answer:it’s c

Explanation:

7 0
3 years ago
A truck on a straight road starts from rest, accelerating at 2.00m/s^2 until it reaches a speed of 20.0m/s. Then the truck trave
Dennis_Churaev [7]

Answer:

Explanation:

a )

Time to reach the speed of 20 m/s with an acceleration of 2 m/s² can be calculated as follows .

v = u + a t

20 = 0 + 2 t

t = 20 /2 = 10 s .

Total time = 10 s + 20 s + 5 s = 35 s .

b) Average velocity = Total distance travelled / total time

Distance travelled in first 10 s

S₁ = ut + 1/2 a t²

= 0 + .5 x 2 x 10²

= 100 m

Distance travelled in next 20 s

S₂= 20s x 20 m/s  = 400 m

Distance travelled in last 5 s .

deceleration in last 5 s

v = u + at

0 = 20 m/s + a x 5

a = - 4 m/s²

v² = u² - 2 a s

0 = (20 m/s)² - 2 x 4 m/s² x s

s = 50 m

S₃ = 50 m

Total distance = S₁ + S₂ + S₃

= 100 m + 400 m + 50 m

= 550 m .

Average velocity = 550 m / 35 s

= 15.71 m /s .

3 0
3 years ago
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