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3 years ago

Planes X and Y and points C, D, E, and F are shown.

Chemistry

2 answers:

maks197457 [2]3 years ago

8 0

Answer:

B. The line that can be drawn through points D and E is contained in plane Y.

Explanation:

Citrus2011 [14]3 years ago

3 0

Answer:

The line drawn through points D and E.

Explanation:

Y is a horizontal line and D and E are both on the same line. If a line were drawn it would be within the Y plane.

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Are two atoms of the same element identical??

Neko [114]

No. Although two such atoms are essentially chemically identical (they will chemically react in the same way), they are not completely identical.

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3 years ago

What is the first step when factoring the trinomial ax^2+bx+c

dlinn [17]

This is all no chemistry but the answer is C

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3 years ago

Calcium carbonate is often used as an antacid. Your stomach acid is composed of HCl at a pH of 1.5. If you ate toooo much Turkey

stiks02 [169]

<u>Answer:</u> 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl

<u>Explanation:</u>

pH is defined as the negative logarithm of hydrogen ion concentration present in the solution

$pH=-\log [H^+]$ .....(1)

Given value of pH = 1.5

Putting values in equation 1:

$1.5=-\log[H^+]$

$[H^+]=10^{(-1.5)}=0.0316M$

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Number of moles of solute}\times 1000}{\text{Volume of solution (mL)}}$ .....(2)

We are given:

Volume of solution = 15.0 mL

Molarity of HCl = 0.0316 M

Putting values in equation 2:

$0.0316=\frac{\text{Moles of HCl}\times 1000}{15.0}\\\\\text{Moles of HCl}=\frac{0.0316\times 15.0}{1000}=4.74\times 10^{-4}mol$

The chemical equation for the reaction of HCl and calcium carbonate follows:

$2HCl+CaCO_3\rightarrow H_2CO_3+CaCl_2$

By the stoichiometry of the reaction:

2 moles of HCl reacts with 1 mole of calcium carbonate

So, $4.74\times 10^{-4}mol$ of HCl will react with = $\frac{1}{2}\times 4.74\times 10^{-4}=2.37\times 10^{-4}mol$ of calcium carbonate

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of calcium carbonate = $2.37\times 10^{-4}mol$

Molar mass of calcium carbonate = 100.01 g/mol

Putting values in the above equation:

$\text{Mass of }CaCO_3=(2.37\times 10^{-4}mol)\times 100.01g/mol\\\\\text{Mass of }CaCO_3=0.0237g$

Hence, 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl

7 0

3 years ago

Sugar dissolving in warm water is chemical or phyiscal change

BlackZzzverrR [31]

Hey there! Great question;) Answer:Physical change Explanation: When sugar mixes with water, at the end, the chemical formulas are the same. Nothing has changed! I hope this helps;)

5 0

3 years ago

The movement of the liquid in a thermometer shows changes in temperature. An increase in temperature indicates the molecules in

olya-2409 [2.1K]

Answer:

2: Moved faster and spread farther apart.

Explanation:

Restate the question: The movement of the liquid in a thermometer shows changes in temperature. An increase in temperature indicates the molecules in the liquid.

1. moved slower and closer together.

2.moved faster and spread farther apart.

3. contracted in size when heated.

4. expanded in size when heated.

Water that is cold does not have the energy to bounce of the walls, instead it is like a group of animals they group together for the warmth of the others when it gets really cold.

So it cant be 1.

We all know that power lines sag lower on a hot day (or a tire for a car, it has increases pressure). but those are different types of molecules.

So that rules out 3 and 4.

Which leaves you with 2.

The increase in temperature causes the water molecule to gain energy and move quickly, which resulted in water molecule that are farther apart and an increase in water volume.

Hope it helps!

7 0

3 years ago

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