Answer:
diplode-diplode interactions
Explanation:
Answer : Total molecules that will be needed to visualize a single egg will be 78500 molecules of dye.
Explanation : As a single egg cell has an approximately diameter of 100 μm.
We can use this formula to calculate area of the cell membrane;
A = π ;
We can take π as 3.14 and we get;
A = 3.14 X
Soving we get;
A = 7850 μ
Here we have to calculate the amount of dye molecules which will be needed for 10 fluorescent molecules / μ but;
here 1 μ = 7850 μ dye molecules.
Therefore, 10 fluorescent molecules will need;
7850 X 10 = 78500 molecules of dye.
Therefore, the answer is 78500 molecules of dye.
Answer:
Violet only
Explination:
Violet is the only color that will eject electrons when it strikes sodium.
Answer:
⇒ (400·3) / 294 = (P2·1) / 277
P2 = 1130.6 kPa
Explanation:
Answer:
Can be produced 288mL of SO₂
Explanation:
Based in the reaction:
P₄S₃ + 8O₂ → P₄O₁₀ + 3SO₂
<em>Where 1 mole of tetraphosphorus trisulfide reacts producing 3 moles of sulfur dioxide gas.</em>
0.869g of tetraphosphorus trisulfide (Molar mass of P₄S₃: 220.09g/mol) are:
0.869g P₄S₃ ₓ (1mol / 220.09g) = 3.948x10⁻³ moles of P₄S₃
As 3 moles of SO₂ are produced per mole of P₄S₃:
3.948x10⁻³ moles of P₄S₃ ₓ (3 moles SO₂ / 1 mole P₄S₃) = 0.0118 moles SO₂
Using PV = nRT
V = nRT / P
<em>Where n are 0.0118 moles, R gas constant (0.082atmL/molK), T absolute temperature (21.0°C + 273.15K = 294.15K), and P pressure (751torr / 760 = 0.988atm).</em>
Replacing:
V = 0.0118molₓ0.082atmL/molKₓ294.15K / 0.988atm
V = 0.288L = 288mL
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