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3 years ago

What are the simplest organic compounds called?

Chemistry

1 answer:

riadik2000 [5.3K]3 years ago

4 0

Answer:

Answer:hydrocarbons

Explanation:

The simplest organic compounds are the hydrocarbons, which contain only carbon and hydrogen. Alkanes contain only carbon–hydrogen and carbon–carbon single bonds, alkenes contain at least one carbon–carbon double bond, and alkynes contain one or more carbon–carbon triple bonds.

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Calculate the molarity of a solution of sodium hydroxide if it contains 0.5 moles in 75ml of solution.

tatuchka [14]

Molarity = moles of solute/volume of solution (L)

0.5 moles/0.075 L = 6.67 M

3 0

3 years ago

A pure substance is found to contain 53.7% fluorine and 46.3% xenon by mass. What is the empirical formula of this substance?

evablogger [386]

Answer: XF8

Explanation:

Empirical Formular shows the simplest ratio of elements in a compound.

Xe = 46.3% F = 53.7%

Divide the percentage composition of each element by the atomic mass.

Xe = 46.3/ 131.3 F= 53.7/ 19

= 0.353( approx) = 2.826 (approx)

Divide through with the smallest of the answers gotten in previous step.

Xe = 0.353 / 0.353 F = 2.826/ 0.353

= 1 = 8.0

Empirical formular = XF8

3 0

3 years ago

PLEASE HELP IT'S URGENT

yuradex [85]

Answer:

Explanation:

4 0

3 years ago

Read 2 more answers

When a test instrument is calibrated, does its accuracy, precision, or reliability improve?

My name is Ann [436]

The answer is accuracy.

That is when a test instrument is calibrated, its accuracy is improved. That is the result comes more close to what it is.

The other factor will not be improved that is its reliability and precision remains the same.

So the answer is accuracy is improved when a test instrument is calibrated.

8 0

3 years ago

Calculate the mass (in grams) of methylene bluecrystals that you must weigh in order to make 100.0mL of 1.25 × 10-5mol/L methyle

mario62 [17]

Answer: The mass of methylene blue that must be weighed is $3.99\times 10^{-4}g$

Explanation:

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = $1.25\times 10^{-5}M$

Molar mass of methylene blue = 319.85 g/mol

Volume of solution = 100.0 mL

Putting values in above equation, we get:

$1.25\times 10^{-5}M=\frac{\text{Mass of methylene blue}\times 1000}{319.85\times 100.0}\\\\\text{Mass of methylene blue}=\frac{1.25\times 10^{-5}\times 319.85\times 100.0}{1000}=3.99\times 10^{-4}g$

Hence, the mass of methylene blue that must be weighed is $3.99\times 10^{-4}g$

4 0

3 years ago